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ruslelena [56]
3 years ago
13

What number is added to 0.034 to obtain 9.079?

Mathematics
2 answers:
Nadya [2.5K]3 years ago
8 0
9.045 is the answer.

You get this by subtracting 0.034 from 9.079
9.079 - 0.034 = 9.045

You can check by adding them back:
9.045 + 0.034 = 9.079

grigory [225]3 years ago
7 0
9.045 is the number added to 0.034 to obtain 9.079
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four girls and one boy are placed in a line what is the probability that the boy is placed in the back?​
Y_Kistochka [10]

Answer: 25 %

Step-by-step explanation: because it would be one fourth

5 0
3 years ago
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Given parallelogram abcd, find the value of y.
nekit [7.7K]

Answer:

c) 82

Step-by-step explanation:

<ABE and <BEC are supplementary because they form a line.

<ABE + <BEC = 180

116+ x = 180

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116-116+x = 180 -116

x = 64


The angles in triangle ECB add to 180 because it is a triangle

<BEC + <ECB + <CBE = 180

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4 0
3 years ago
What is the distance of P(1,-3) from y- axis​
madam [21]

Answer:

1 unit to the right

Step-by-step explanation:

The y-axis is the vertical line and the point (1,-3) is one unit to the right of the vertical line

3 0
3 years ago
Can someone please help me with these?
Vikki [24]

Answer:

  Ⓒ  {1, 2, 3, 6, 9, 13, 14}

Step-by-step explanation:

One way to find the union of two sets is to list all the elements of both sets in order, then delete any duplicates.

Here, joining the two sets gives ...

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Putting these elements into numerical order, we have ...

  {1, 1, 2, 2, 3, 6, 9, 13, 14}

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8 0
3 years ago
Solve.
Ksenya-84 [330]
<span>Solve.

x² + 4x + 4 = 18


​ A x=−4±3√ ​2

​ B x=2±3√ ​2

​ C x=4±9√ ​2

D x=−2±3√2



</span>x^2 + 4x + 4 = 18 \\  \\ x^2+4x+4-18= 0 \\  \\ x^2+4x-14=0 \\  \\ x_1_y_2=  \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{16-(-56)} }{2}  \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{72} }{2}  \\  \\  \\  x_1=  \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2=  \dfrac{-4+ \sqrt{72} }{2}\\  \\  \\  x_1=  \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2=  \dfrac{-4- \sqrt{2^3*3^2} }{2}
<span>
</span>x_1=  \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2=  \dfrac{-4- 2*3\sqrt{2} }{2} \\  \\  \\ x_1=  \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2=  \dfrac{-4- 6\sqrt{2} }{2} \\  \\  \\ x_1=  \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2=   \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\  \\  \\  x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad  x_2=  -2- 3\sqrt{2}  \\  \\  \\ \boxed{x=   -2\pm 3\sqrt{2} }  \to D)<span>
</span>
7 0
3 years ago
Read 2 more answers
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