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garri49 [273]
2 years ago
8

Explain how our kidneys filter water and how the universal solvent properties important in that process

Chemistry
1 answer:
ddd [48]2 years ago
7 0

Kidneys filter water as Kidneys filter the substance that enters our body using water because water dissolves these substance and send them out of our body. The universal property of water plays a important role in this process as it wash out a great portion even all the substance in our body.

So kidneys filter water and the universal solvent properties plays a important role  in that process.



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ivann1987 [24]

Answer:

11.43 cm

Explanation:

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Hydrazine, N2H4, is a corrosive liquid used in rocket and jet fuels. Ammonia, NH3, is a gas that dissolves in water to form a so
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OK in the case of hydrazine  14 grams of nitrogen  combine with 2 gram of hydrogen and with ammonia 14 grams combine with 3 grams of hydrogen.

Ratio 2:3
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32. Barium sulfate, BaSO4, is a white crystalline solid that is insoluble in water. It is used by doctors to diagnose
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HELP.....From the information presented in the activity series of metals below (4 metals included), answer the following questio
san4es73 [151]

Answer:

a)there would be no reaction

Explanation:

The activity series of metals has many functions. The one applicable to this problem is that it can be used to determine whether a reaction will occur or not. Also, based on the positions of metals in the series, we can know how reactive a metal is compared to another.

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Would aluminum replace magnesium to form a new compound or would there be no reaction?

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6 0
2 years ago
1 mol super cooled liquid water transformed to solid ice at -10 oC under 1 atm pressure.
Arada [10]

Answer:

Explanation:

Given that:

number of moles of super cooled liquid water = 1

Melting enthalpy of ice = 6020 J/mol

Freezing point =0 °C = (0 + 273 K)= 273 K

The decrease in entropy of the system during freezing for 1 mol (i.e during transformation from liquid water to solid ice )  = - 6020 J/mol × 1 mol /273 K = -22.051 J/K

Entropy change during further cooling from 0 °C (273 K) to -10 °C (263 K)

\Delta \ S = \int\limits^{T_2}_{T_1}\dfrac{nC_p(s)dT}{T}

\Delta \ S = {nC_p(s)In \dfrac{T_2}{T_1}

\Delta \ S = {(1*37.7)In \dfrac{263}{273}

Δ S = -1.4 J/K

Total entropy change of the system = - 22.05 J/K - 1.4 J/K = - 23.45 J/K

Entropy change of universe = entropy change of the system+ entropy change of the surrounding

According to the second law of thermodynamics

Entropy change of universe  >0

SO,

Entropy change of the system + entropy change in the surrounding > 0

Entropy change in the surrounding > - entropy change of the system

Entropy change in the surrounding > - (- 23.53 J/K)

Entropy change in the surrounding > 23.53 J/K

b) Make some comments on entropy changes from the obtained data.

From the data obtained; we will realize that the entropy of the system decreases as cooling takes place when water is be convert to ice , randomness of these molecules reduces and as cooling proceeds , hence, entropy reduces more as well and the liberated heat will go into the surrounding due to this entropy of the surrounding increasing.

4 0
2 years ago
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