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Need asap! Step-by-step pls: Determine the empirical formula: 32.37% Na, 22.58% S, 45.05% O

Ludmilka [50]

1) divide each percentage by the relative atomic mass of the element

2) divide all results by the smallest number

3)multiply by a whole number to get the simplest whole number ratio (if necessary)

that is to say:

Na S O

32.37÷23 22.58÷32 45.05÷16

= 1.407 = 0.7056 = 2.816 (to 4 significant figures)

the smallest number here is 0.7056 so:

1.407÷0.7056 0.7056÷0.7056 2.816÷0.7056

=1.99 approx.2 = 1 3.99 approx. 4

here there is no need to carry out step 3 as ratio obtained is already a simplest whole number ratio

so empirical formula is: Na₂SO₄

8 0

2 years ago

How many branches of chemistry are there .

faltersainse [42]

Answer:

5

Explanation:

Analytical chemistry

Organic chemistry

Inorganic chemistry

physical chemistry

Biochemistry

6 0

2 years ago

Read 2 more answers

A 1.24g sample of a hydrocarbon, when completely burned in an excess of O2 yields 4.04g Co2 and 1.24g H20. Draw plausible struct

arsen [322]

Answer:

Plausible structure has been given below

Explanation:

Molar mass of $CO_{2}$ is 44 g/mol and molar mass of $H_{2}O$ is 18 g/mol
Number of mole = (mass/molar mass)

4.04 g of $CO_{2}$ = $\frac{4.04}{44}moles$ $CO_{2}$ = 0.0918 moles of $CO_{2}$

1 mol of $CO_{2}$ contains 1 mol of C atom

So, 0.0918 moles of $CO_{2}$ contains 0.0918 moles of C atom

1.24 g of $H_{2}O$ = $\frac{1.24}{18}moles$ $H_{2}O$ = 0.0689 moles of $H_{2}O$

1 mol of $H_{2}O$ contain 2 moles of H atom

So, 0.0689 moles of $H_{2}O$ contain $(2\times 0.0689)moles$ of $H_{2}O$ or 0.138 moles of $H_{2}O$

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is $C_{2}H_{3}$

So, molecular formula of one of it's analog is $C_{4}H_{6}$

Plausible structure of $C_{4}H_{6}$ has been given below.

4 0

2 years ago

What is the correct order of earths six convection cells , from the North Pole to the South Pole

makkiz [27]

polar, Hadley, Ferrel, polar, Hadley, Ferrel. I hope this helps you.

4 0

2 years ago

Formula New Combination Predicted Formula

creativ13 [48]

Answer:

Formula New Combination Predicted Formula


NaCl potassium + chlorine KCl

AlCl₃ aluminum + fluorine AlF₃

CO₂ tin + oxygen SnO₂

MgCl₂ calcium + bromine CaBr₂

HCl cesium + iodine CsI

 CCl₄ silicon + bromine SiBr₄

Explanation:

1) The question is incomplete. The first part is missing.

This is the first part of the question.

Applying the principle that the elements of a particular column in the Periodic Table share the same chemical properties, complete the following chart. The first one has been done for you.


2) This is the given chart:

Formula New Combination Predicted Formula


Cu₂O silver + oxygen Ag₂O ← this is the example.

NaCl potassium + chlorine

 AlCl₃ aluminum + fluorine 

CO₂ tin + oxygen

 MgCl₂ calcium + bromine 

 HCl cesium + iodine 

 CCl₄ silicon + bromine 

3) This is how you find the new formula to complete the chart.

i) NaCl potassium + chlorine

Since potassium is in the same group of sodium, you predict that in the new formula Na is replaced by K giving KCl.

ii) AlCl₃ aluminum + fluorine

Since fluorine is in the same group that Al, then you predict that in the new formula Cl is replaced by F leading to AlF₃

iii) CO₂ tin + oxygen

Since tin is in the same group that C, you predict that in the new formula C is replaced by Sn leading to SnO₂

iv) MgCl₂ calcium + bromine

Since calcium is in the same group that Mg, and bromine is in the same group that Cl, you predict thea in the new formula calcium replaces Mg and bromine replaces Cl, leading to CaBr₂

v) HCl cesium + iodine

Since H is in the same column that cesium and Cl is in the same colum that iodine, you predict that in the new formula Cs replaces H and I replaces Cl leading to: CsI

 vi) CCl₄ silicon + bromine


Since silicon is in the same column that C and bromine is in the same column that Cl, you predict that in the new formula Si replaces C and Br replaces Cl, leading to SiBr₄

5 0

2 years ago