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ivann1987 [24]
2 years ago
12

What is observed when magnesium is reacted with hydrochloric acid? choose all that apply

Chemistry
1 answer:
Zanzabum2 years ago
3 0

It is observed that when magnesium reacts with hydrochloric acid, it produces visible bubbles of hydrogen gas.

A vigorous reaction will occur giving rise of heat as it is an exothermic reaction. If heat is applied then it should be more vigorous.

Reaction is as follows:

Mg(s) + HCl (aq) --> MgCl2 (aq) + H2(g)

Magnesium reacts easily with HCl to produce H2 gas and magnesium ions, Mg2+, and heat. The reaction is exothermic, so it heats up quickly.

Mg(s) + HCl (aq) --> MgCl2(aq) + H2(g)

The net ionic equation :

Mg(s) + 2H+ --> Mg2 + H2(g)

If water is removed from the solution then white crystals of Mgcl2 is obtained.

Or in simple words,

2Mg + 2HCl -> 2Mg+ + 2Cl- + H2(gas)

The magnesium is attacked by the hydrochloric acid resulting in the magnesium dissolving into the solution resulting in a solution of magnesium chloride in hydrochloric acid and the production of hydrogen gas.

Learn more about magnesium here : brainly.com/question/5759562

#SPJ4

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0.72-mol sample of is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of and 0.40 mol of . Cal
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0.50

Explanation:

<em>A 0.72-mol sample of PCl₅ is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of PCl₃(g) and 0.40 mol of Cl₂(g). Calculate the value of the equilibrium constant for the decomposition of PCl₅ to PCl₃ and Cl₂ at this temperature. </em>

<em />

Step 1: Calculate the molar concentrations

[PCl₅]i = 0.72 mol/1.00 L = 0.72 M

[PCl₃]eq = 0.40 mol/1.00 L = 0.40 M

[Cl₂]eq = 0.40 mol/1.00 L = 0.40 M

Step 2: Make an ICE chart

        PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

I        0.72           0            0

C         -x            +x          +x

E      0.72-x          x           x

Step 3: Determine the value of x

Since [PCl₃]eq = [Cl₂]eq = 0.40 M, x = 0.40 M

Step 4: Determine the concentration of PCl₅ at equilibrium

[PCl₅]eq = 0.72-x = 0.72-0.40 = 0.32 M

Step 5: Calculate the equilibrium constant

Kc = [PCl₃] × [Cl₂] / [PCl₅]

Kc = 0.40 × 0.40 / 0.32 = 0.50

4 0
3 years ago
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