Answer:
625 mL
Explanation:
From the question given above, the following data were obtained:
Volume of stock solution (V₁) = 250 mL
Molarity of stock solution (M₁) = 5 M
Molarity of diluted solution (M₂) = 2 M
Volume of diluted solution (V₂) =?
The volume of the diluted solution can be obtained by using the dilution formula as illustrated below:
M₁V₁ = M₂V₂
5 × 250 = 2 × V₂
1250 = 2 × V₂
Divide both side by 2
V₂ = 1250 / 2
V₂ = 625 mL
Therefore, the volume of the diluted solution is 625 mL.
Answer:
3.01 ·10↑22
Explanation:
First you want to convert the grams of Glucose to moles of Glucose.
Next find the formula units of glucose.
.008326Moles of Glucose · 6.022 · 10↑23Forumula Units*Moles↑-1 =
5.01 ·10↑21 Formula Units of Glucose
Now multiply the formula units of glucose by the amount of each element in the molecule.
So for Carbon:
6carbon · 5.01 · 10↑21 = 3.01 · 10↑22
(please mark as Brainliest)
Answer:
The correct option is: B. Carbon 5 only
Explanation:
Carvone is a naturally-occurring monoterpenoid consisting of a six-membered cyclic ring. <u>The </u><u><em>carbon-5</em></u><u> of this cyclic ring of Carvone is </u><u><em>chiral, </em></u><u>due to which Carvone exhibits </u><u><em>enantiomerism</em></u><u>.</u>
The two <em>enantiomeric forms</em> of Carvone are: R-(–)-carvone, or L-carvone, and S-(+)-carvone, or D-carvone.
<em><u>These two enantiomeric forms differ in the orientation of the substituents on the chiral carbon-5.</u></em>
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<u>Therefore, the correct option is B. Carbon 5 only.</u>
Answer is: the identity of the isotope is silver (Ag-107).
p⁺(isotope) = 47; number of protons in isotope.
Z = p⁺; atomic number.
Atomic number is the number of protons, which is characteristic of a chemical element, silver is an element with atomic number 47.
n°(isotope) = 60; number of neutrons in isotope.
A = p⁺ + n°; mass number is the total number of protons and neutrons in a nucleus.
A = 47 + 60.
A = 107.
Well on a side note, a mole in chemistry is also the same as a Liter. A mole however, is the mass of an element,or compound. 1 mol of O would be 15.9994 grams/mol. It can also be represented as 6.022*10 to the 23 power. (1 mol of Carbon-12 atoms)
