For #4, we know V = lwh
We have the values
5184 = 2(18)h
Solve for h
5184 = 36h
144 = h.
for # 3:
we know A = pi r^2
We have
A = 3.14 * 6^2
A = 3.14 * 36
A = 113.04
for #2:
We know C = 2pi *r
C = 2(3.14)(14)
C = 28(3.14)
C = 87.92
for #1:
C = 2pi * r
C = 2(3.14)(26.3/2)
C = 2(3.14)(13.15)
C = 26.3(3.14)
C = 82.582
Find the area of the triangle and the multiply by the depth of the solid.
Area = 1/2 x base x height
Area = 1/2 x 3 x 5
Area = 7.5 sq. ft.
Volume = 7.5 x 4 = 30 cubic ft.
Answer:
A
Step-by-step explanation:
Because the x-coordinate is in seconds. Which eliminates answer B
Also, the Y-coordinate is measured in 40 meters per unit, this eliminates C and D.
Answer:
1. m = 6/5 or 1 1/5
2. m = -4/5
Step-by-step explanation:
1.) Find the slope of the line that contains (5,4) and (0,−2).
Slope m = (y2-y1)/(x2-x1)
m = (-2 - 4)/(0 - 5) = -6/-5 = 6/5
m = 1 1/5
2.) Find the slope of the line that contains (6,−2) and (−4,6).
Slope m = (y2-y1)/(x2-x1)
m = (6 - -2)/(-4 - 6) = 8/-10 = -8/10 = -4/5
Answer:
"perpendicular"
Step-by-step explanation:
We need to find slope (m) of both line JK and LM
Slope has formula:
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Lets find slope of JK:
![m=\frac{4-9}{7-1}\\m=-\frac{5}{6}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B4-9%7D%7B7-1%7D%5C%5Cm%3D-%5Cfrac%7B5%7D%7B6%7D)
Lets find slope of LM:
![m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{1-13}{-2-8}\\m=\frac{6}{5}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%5C%5Cm%3D%5Cfrac%7B1-13%7D%7B-2-8%7D%5C%5Cm%3D%5Cfrac%7B6%7D%7B5%7D)
we know if we multiply two lines' slope and get -1, they are perpendicular. Let's check:
![-\frac{5}{6}*\frac{6}{5}=-1](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%2A%5Cfrac%7B6%7D%7B5%7D%3D-1)
Hence, they are perpendicular