I am going to say C. it has to do with the angles
equilibrium
Heat transfers from a body with high temperature to a body with low temperature until both bodies are in the same temperature.
Answer: Final temperature = 206∘C
Explanation:
Heat Energy is given as
q= mCΔT
ehere
q= Heat energy = 87.4J
m= mass=1.25g
C=specific heat c= 0.386Jg∘C) ,
ΔT = Change in temperate of which the final temperature= 25.0∘C
q= mCΔT
ΔT = q/mC
ΔT = 87.4/ 1.25 X 0.386=181.14∘C
But,
T final- T initial = ΔT
T final = T initial + ΔT
T final = 25.0∘C +181.14∘C=206.14∘C rounded to 206∘C
Answer: 36.53g
Explanation:
First we need to find the amount of NaCl that dissolves in 1L of the solution that produced 5M of NaCl
Molarity = 5M
MM of NaCl = 58.45
Molarity = Mass conc (g/L) / MM
Mass conc. (g/L) of NaCl = Molarity x MM
= 5 x 58.45 = 292.25g
Next, we need to find the amount that will dissolve in 125mL(i.e 0.125L)
From the calculations above,
292.25g of NaCl dissolved in 1L
Therefore Xg of NaCl will dissolve in 0.125L of the solution i.e
Xg of NaCl = 292.25 x 0.125 = 36.53g.
Therefore 36.53g of NaCl will dissolve in 125mL of the solution
26.25g
Explanation:
Given parameters:
Percentage of NaCl in ocean water = 3.5%
Mass of given seawater = 750g
Unknown:
Mass of NaCl in the seawater = ?
Solution:
This is a simple percentage problem:
We have been given that ocean water contains 3.5% of NaCl;
Therefore;
Mass of NaCl in seawater = Percentage of NaCl in ocean water x Mass of seawater
Mass of NaCl in seawater = 
x 750g = 26.25g
Learn more:
Percentage brainly.com/question/2917248
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