Answer:
- 1. Iodine is the limiting reactant
- 2.
Explanation:
<u>1. Balanced chemcial equation:</u>
<u>2. Theoretical mole ratio</u>
It is the ratio of the coefficients of the reactants in the balanced chemical equation:
<u>3. Actual ratio</u>
<u />
It is ratio of the moles available to reat:
<u>4. Comparison</u>
Then, there are more aluminum available than what is needed to react with the 9 moles of iodine, meaning that the aluminum is in excess and the iodine will react completely, being the latter the limiting reactant.
Conclusion: iodine is the limiting reactant.
<u>5. How much aluminum iodide will be produced?</u>
Use the theoretical mole ratio of aluminum iodide to iodide:
Answer:2817.8
Explanation:multiply the value by 365
Answer:
Explanation:
a) O (oxygen) but there's not enough info to determine the isotope
b) superscript-37 subscript-17 Cl
c) superscript-60 subscript-27 Co
d) superscript-57 subscript-26 Fe
e) don't know what you mean here
f) superscript-7 subscript-3 Li
Edit:
a) superscript-17 subscript-8 O
e) superscript-131 subscript-53 I
Answer:
8.55 × 10³ cal
Explanation:
Step 1: Given and required data
- Specific heat of water (c): 1 cal/g.°C
- Initial temperature: 22.7 °C
- Final temperature: 38.8 °C
Step 2: Calculate the temperature change (ΔT)
ΔT = Final temperature - Initial temperature = 38.8 °C - 22.7 °C = 16.1 °C
Step 3: Calculate the heat required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 1 cal/g.°C × 531 g × 16.1 °C = 8.55 × 10³ cal
