430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
<h3>What is Molarity?</h3>
- The amount of a substance in a specific volume of solution is known as its molarity (M).
- The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>
Remember that mol/L is the unit of molarity (M).
We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.
0.75L×4.0M=3.0mol
Then, using the periodic table's molar mass for AgCl, convert from moles to grams:
3.0mol×143.321gmol=429.963g
The final step is to round to the correct significant figure, which in this case is two: 430g.
Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
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<u>Answer:</u> The correct answer is Option D.
<u>Explanation:</u>
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients. It is represented by 
For a general chemical reaction:
The is written as:
![K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
There are 3 conditions:
- When
; the reaction is product favored. - When
; the reaction is reactant favored. - When
; the reaction is in equilibrium.
At equilibrium, the ratio of concentration of reactants to the concentration of products is equal to 1.
At equilibrium, the rate of forward reaction is equal to rate of backward reaction.
Hence, the correct answer is Option D.
H3PO4 + H2O <--> H3O+ + H2PO4- Ka1= ([H3O+][H2PO4-])/[H3PO4])
H2PO4- + H2O <--> H3O+ + HPO4^2- Ka2= ([H3O+][HPO4^2-])/[H2PO4-])
HPO4^2- + H2O <--> H3O+ PO4^3- Ka3= ([H3O+][PO4^3-])/[HPO4^2-])
Ka1 >> Ka2 = almost all the H3O+ is formed in the first step.
Ka3 will only happen under very basic conditions.
