1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sertanlavr [38]
3 years ago
12

63°C = _____ 63 K 336 K 210 K 163 K

Physics
2 answers:
Xelga [282]3 years ago
4 0

Answer : The temperature in Kelvin is 336 K.

Explanation :

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273+^oC

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in degree Celsius is, 63^oC

Now we have to determine the temperature in Kelvin.

K=273+^oC

K=273+63

K=336

Therefore, the temperature in Kelvin is 336 K

Nata [24]3 years ago
3 0
Is is the second one. 336 k. 273.15K= 0C.
You might be interested in
The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the c
maria [59]

To solve this problem we will start using the concepts related to the electric field, from there we will find the load exerted on the body. Through this load it will be possible to make a sum of forces in balance to find the load that a human supports. Finally with these values it will be possible to find the repulsive force. We will proceed as follows,

The electric field is

E= \frac{kQ}{R^2}

Here,

k = Coulomb's Constant

Q = Charge

R = Distance (At this case from the center of mass of the earth to the surface)

Rearranging to find the charge,

Q = \frac{ER^2}{k}

Replacing,

Q = frac{(150)(6.38*10^6)}{8.99*10^9}

Q = 6.79*10^5 C

Since the electric field is directed towards the center of earth, the charge is negative.

PART A) Once the load is found we can proceed to apply the balance of Forces, for which the electrostatic force must be equivalent to the weight, this in order to satisfy the balance, therefore

F_w = F_e

mg = \frac{kQq}{R^2}

Replacing,

(62)(9.8) = \frac{(8.99*10^9)(q)(-6.79*10^5)}{(6.38*10^6)^2}

Solving for q,

q = -4.056C

PART B) Finally using the given distance and the values of the found load we can find the repulsive Force, which is

F =\frac{kq^2}{d^2}

F = \frac{(8.99*10^9)(-4.056)^2}{110^2}

F = 1.22*10^7N

PART C) The answer is no. According to the information found, we can conclude that traveling through an electric field is not viable because there is a repulsive force of great magnitude acting on the body.

3 0
3 years ago
Bob is pulling a 30kg filing cabinet with a force of 200n , but the filing cabinet refuses to move. the coefficient of static fr
puteri [66]
The cabinet is being pulled with 200N and is being rested by a force equal to 200N. That is why it is not being moved. 


<span>Although the force of static friction can equal Fk=µs*F=m*g*µs=(30kg)*(9.8m/s^2)*(0.80)=235 N. It is not resisting the 200N force with 235N. Imagine if you pushed something with 200N and it pushed you back with 235N, especially a cabinet. You would think that the cabinet was alive.</span>
8 0
3 years ago
Calculate the angular velocity of the earth in its orbit around the sun.
Orlov [11]

Answer:

0.0172rad/day=1.99x10^{-7}rad/second

Explanation:

The definition of angular velocity is as follows:

\omega=2\pi f

where \omega is the angular velocity, and f is the frequency.

Frequency can also be represented as:

f=\frac{1}{T}

where T is the period, (the time it takes to conclude a cycle)

with this, the angular velocity is:

\omega=\frac{2\pi}{T}

The period T of rotation around the sun 365 days, thus, the angular velocity:

\omega=\frac{2\pi}{365days}=0.0172rad/day

if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:

Firt conveting to hous

365days(\frac{24hours}{1day} )=8760hours

then to minutes

8760hours(\frac{60minutes}{1hour} )=525,600minutes

and finally to seconds

525,600minutes(\frac{60seconds}{1minute})=31,536x10^3seconds

thus, angular velocity in rad/second is:

\omega=\frac{2\pi}{31,536x10^3seconds}=1.99x10^{-7}rad/second

3 0
3 years ago
a vertical solid steel post 29cm in diameter and 2.0m long is required to support a load of 8200kg, ignore the weight of the pos
erik [133]

Answer:

The stress is  \sigma  =  1.218*10^{6} \  N/m^2

Explanation:

From the question we are told that

   The diameter of the post is  d =  29 \ cm  =  0.29 \  m

   The length is L  =  2.0 \  m

    The weight of the loading mass

Generally  the  radius of the post is mathematically represented as

     r =  \frac{0.29}{2}

=>   r = 0.145 \  m

Generally the area of the post is  

       A =  \pi r^2

=>     A =  3.14 *  0.145 ^2

=>     A =  0.066 \ m^2

Generally the weight exerted by the load is mathematically represented as

        F =  m  *  g

=>      F =  8200  *  9.8

=>      F =  80360 \  N

Generally the stress is mathematically represented as

         \sigma  =  \frac{F}{A}

=>      \sigma  =  \frac{80360 }{0.066}

=>      \sigma  =  1.218*10^{6} \  N/m^2

7 0
2 years ago
HELP ASAP!! The voltage from a power supply to a light bulb is increased by 2 volts and the current is recorded. A graph of this
uysha [10]

Answer:

It is a resistor since as u increases v increases so they are directly propotional

3 0
3 years ago
Other questions:
  • Which of the following is one way that technology can improve procut<br> ?
    13·1 answer
  • What helps determine how easily magma flows?
    6·1 answer
  • Divers in Acapulco, Mexico, leap from a point 36m above the sea. What is the velocity when they enter the water? V = distance /
    8·2 answers
  • Why do some coastal cities experience a moderation of temperature from water?
    8·1 answer
  • Which of these experiments would make use of qualitative data?
    15·2 answers
  • two girls drag a bag across the floor. One girl exerts a force of 10 newtons and the other girl a force of 30 Newton's in the sa
    9·1 answer
  • 18. Write conversion factors (as ratios) for the number of:
    10·1 answer
  • What are conspiracy theories?​
    13·1 answer
  • I'm confused! Please help me if you can!
    15·2 answers
  • The next closest star to Earth, Proxima Centuri, is 4.25 lightyears away. How far is that in meters?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!