Explanation:
It is given that,
Initially the car is at rest and travels for t₁ seconds with a uniform acceleration a₁. The driver then applies the brakes, causing a uniform acceleration a₂, If the brakes are applied for t₂ seconds.
We need to find the speed of the car just before the beginning of the braking period.
Using the formula of acceleration. It is given by :
u = 0
So, just before the beginning of the braking period the speed of the car is 
. Hence, this is the required solution.
The names given to the Moon by the Algonquin are as follows:
January- Full Wolf Moon
February- Full Snow Moon
March- Full Worm Moon
April- Full Pink Moon
May- Full Flower Moon
June- Full Strawberry Moon
July- Full Buck Moon
August- Full Sturgeon Moon
September- Full Corn Moon; Full Harvest Moon
October- Full Hunter's Moon
November- Full Beaver Moon
December- Full Cold Moon; Full Long Nights Moon
To find the x component use the following formula, where Ф = theta = the angle 'a' makes with the x axis.
Answer:
the time interval that an earth observer measures is 4 seconds
Explanation:
Given the data in the question;
speed of the spacecraft as it moves past the is 0.6 times the speed of light
we know that speed of light c = 3 × 10⁸ m/s
so speed of spacecraft v = 0.6 × c = 0.6c
time interval between ticks of the spacecraft clock Δt₀ = 3.2 seconds
Now, from time dilation;
t = Δt₀ / √( 1 - ( v² / c² ) )
t = Δt₀ / √( 1 - ( v/c )² )
we substitute
t = 3.2 / √( 1 - ( 0.6c / c )² )
t = 3.2 / √( 1 - ( 0.6 )² )
t = 3.2 / √( 1 - 0.36 )
t = 3.2 / √0.64
t = 3.2 / 0.8
t = 4 seconds
Therefore, the time interval that an earth observer measures is 4 seconds
Answer:
attracted
Explanation:
Electrons are negative.
A positively charged object will attract a negatively charged object
