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mr Goodwill [35]
3 years ago
9

two girls drag a bag across the floor. One girl exerts a force of 10 newtons and the other girl a force of 30 Newton's in the sa

me direction. Calculate the resultant force on the bag.​
Physics
1 answer:
lara [203]3 years ago
5 0

Answer:

Explanation:

The resultant would be a combination of the two forces. We need to add them together since they are exerting a force in the same direction.

10+30= 40 N of force

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To calculate for the pressure of the system, we need an equation that would  relate the number of moles (n), pressure (P), and temperature (T) with volume (V). There are a number of equations that would relate these values however most are very complex equations. For simplification, we assume the gas is an ideal gas. So, we use PV = nRT.<span>

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While riding on I-26 towards Columbia, your mother slams on the brakes, to avoid hitting the car in front of her. Both of your b
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Two radio antennas A and B radiate in phase. Antenna B is a distance of 130 m to the right of antenna A. Consider point Q along
hoa [83]

Answer:

constructive  λ = 130 m

destructive  λ = 260 m

Explanation:

a) the expression for constructive interference is that the difference in amino is equal to a multiple of the average wavelength

                   AQ - BQ = 2m λ/ 2       m = 0, 1, 2, ...

                     

Where

     AQ = 130 +50 = 180 m

     BQ = 50 m

To find the smallest wavelength let's use m = 1

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b) for destructive interference

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                  λ = 260 m

3 0
3 years ago
A series circuit has a capacitor of 0.25 × 10⁻⁶ F, a resistor of 5 × 10³ Ω, and an inductor of 1H. The initial charge on the cap
viktelen [127]

Answer:

q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}

at t = 0.001 we have

q = 1.55 \times 10^{-6} C

at t = 0.01

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at t = infinity

q = 3 \times 10^{-6} C

Explanation:

As we know that they are in series so the voltage across all three will be sum of all individual voltages

so it is given as

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now we will have

iR + L\frac{di}{dt} + \frac{q}{C} = 12 V

now we have

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at t = 0 we have

q = 0

0 = 3\times 10^{-6} + c_1  + c_2

also we know that

at t = 0 i = 0

0 = -4000 c_1 - 1000c_2

c_2 = -4c_1

c_1 = 1 \times 10^{-6}

c_2 = -4 \times 10^{-6}

so we have

q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}

at t = 0.001 we have

q = 1.55 \times 10^{-6} C

at t = 0.01

q = 2.99 \times 10^{-6} C

at t = infinity

q = 3 \times 10^{-6} C

5 0
3 years ago
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