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Andrej [43]
3 years ago
10

18. Write conversion factors (as ratios) for the number of:

Physics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

Conversion tables show:

1 m = 1.09361 yds

1 Lit = .26418 gal = 1.05672 qt     or 1 qt = .944632 Lit

1 lb = .45359 kg = 2.2046 Lbs / Kg

So X yds = X  m * 1.09361 yds / m = 1.09361 * X yds

Likewise X Lit  = X  qt  / 1.05672 qt/ Lit = X / 1.05672 Lit = .94632  X Lit

So X  Lbs =  X kg * 2.2046 Lbs / Kg = 2.2046 Lbs

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Ammeter is used to measure the current in a circut 
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3 years ago
A truck travelled at a constant speed for 6 hours. Then , it decreased itd speed by 13 mph for the remaining 228 miles. If the t
kakasveta [241]

Answer:

 Time taken to travel remaining 228 miles = 2.4 hours.

Explanation:

Total distance = 876 miles.

Distance traveled after speed reduction = 228 miles

So, distance traveled before = 876 - 228 =648 miles.

Time taken for this = 6 hours.

Speed before speed reduction = 648/6 = 108 mph.

Speed after speed reduction = 108 - 13 = 95 mph

Time taken to travel remaining 228 miles = 228/95 = 2.4 hours.

7 0
3 years ago
Which of the following is equal to the area under a velocity-time graph
Ksenya-84 [330]

-- The area under a velocity/time graph, between two points in time, is the difference in displacement during that period of time.

-- The area under a speed/time graph, between two points in time, is the distance covered during that period of time.

5 0
3 years ago
Read 2 more answers
A large crate with mass m rests on a horizontal floor. The static and kinetic coefficients of friction between the crate and the
Mariana [72]

a) F=\frac{\mu_k mg}{cos \theta - \mu_k sin \theta}

Here the crate is moving at constant velocity, so no acceleration:

a = 0

Let's analyze the forces acting along the horizontal and vertical direction.

- Vertical direction: the equation of the forces is

R-Fsin \theta - mg = 0 (1)

where

R is the normal reaction of the floor (upward)

F sin \theta is the component of the force F in the vertical direction (downward)

mg is the weight of the crate (downward)

- Horizontal direction: the equation of the forces is

F cos \theta - \mu_k R = 0 (2)

where

F cos \theta is the horizontal component of the force F (forward)

\mu_k R is the force of friction (backward)

From (1) we get

R=Fsin \theta +mg

And substituting into (2)

F cos \theta - \mu_k (Fsin \theta +mg) = 0\\F cos \theta -\mu _k F sin \theta = \mu_k mg\\F(cos \theta - \mu_k sin \theta) = \mu_k mg\\F=\frac{\mu_k mg}{cos \theta - \mu_k sin \theta}

b) \mu_s=cot(\theta)

In this second case, the crate is still at rest, so we have to consider the static force of friction, not the kinetic one.

The equations of the forces will be:

R-Fsin \theta - mg = 0 (1)

F cos \theta - \mu_s R = 0 (2)

In this second case, we want to find the critical value of \mu_s such that the woman cannot start the crate: this means that the force of friction must be at least equal to the component of the force pushing on the horizontal direction, F cos \theta.

Therefore, using the same procedure as before,

R=Fsin \theta +mg

F cos \theta - \mu_s (Fsin \theta +mg) = 0

And solving for \mu_s,

F cos \theta = \mu_s (Fsin \theta +mg) \\\mu_s = \frac{F cos \theta}{F sin \theta + mg}

Now we analyze the expression that we found. We notice that if the force applied F is very large, F sin \theta >> mg, therefore we can rewrite the expression as

\mu_s \sim \frac{F cos \theta}{F sin \theta}\\\mu_s=cot(\theta)

So, this is the critical value of the coefficient of static friction.

8 0
3 years ago
Need help asap pls
ozzi
Detailed Explanation:

1) Rusting of Iron

4Fe + 3O2 + 2H2O -> 2Fe2O32H2O

Reactants :-
Fe = 4
O = 3 * 2 + 2 = 8
H = 2 * 2 = 4

Products :-
Fe = 2 * 2 = 4
O = 2 * 3 + 2 = 8
H = 2 * 2 = 4

2) Fermentation of sucrose…

C12H22O11 + H2O -> 4C2H5OH + 4CO2

Reactants :-
C = 12
H = 22 + 2 = 24
O = 11 + 1 = 12

Products :-
C = 4 * 2 + 4 = 12
H = 4 * 5 + 4 = 24
O = 4 * 2 + 4 = 12

Looking closely at the way I have taken the total number of elements on the reactants and products side, you can solve the rest.

All the Best!
8 0
3 years ago
Read 2 more answers
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