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Andrej [43]
3 years ago
10

18. Write conversion factors (as ratios) for the number of:

Physics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

Conversion tables show:

1 m = 1.09361 yds

1 Lit = .26418 gal = 1.05672 qt     or 1 qt = .944632 Lit

1 lb = .45359 kg = 2.2046 Lbs / Kg

So X yds = X  m * 1.09361 yds / m = 1.09361 * X yds

Likewise X Lit  = X  qt  / 1.05672 qt/ Lit = X / 1.05672 Lit = .94632  X Lit

So X  Lbs =  X kg * 2.2046 Lbs / Kg = 2.2046 Lbs

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Why does the frequency of a siren get higher as an ambulance using that siren gets closer
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As a train accelerates uniformly, it passes successive 5-kilometer markers while traveling at velocities 10 m/s and 25 m/s. what
gregori [183]
<span>122.0 km/hr. First let’s make sure all of our units are in the base meter form: i.e. convert 5km to 5000m. (We will convert back to km later). The first thing to do is look at the equation relating velocity, acceleration, and distance: Vf^2 = Vi^2 + 2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is distance. 25^2 = 10^2 + 2*a*5000 =?> 625 = 100 +10000a => a= 0.0525m/s^2. Now that we have acceleration, we can use the same equation again with different numbers.: Vf^2 = Vi^2 + 2*a*d = 25^2 + 2*0. 0525m*5000 = 625 + 525 =1150 => Vf^2 = 1150 => 33.9m/s. Convert to km/hour: 33.9m/s * 1km/1000m *60s/1min * 60min/ 1 hr = 122.0 km/hr.</span>
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4 years ago
A 12 kg object speeds up from an initial velocity of 10 m:s-1
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5 0
3 years ago
Daisy walks across a force platform, and forces exerted by her foot during a step are recorded. The peak velocity reaction force
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Answer:

(a). The resultant of these forces is 1216.55 N.

(b).  The direction of the resultant forces is 80.53°.

Explanation:

Given that,

First force = 1200 N

Second force = 200 N

(a). We need to calculate the resultant of these forces

Using cosine law

F=\sqrt{F_{1}^2+F_{2}^2+2F_{1}F_{2}\cos\theta}

Put the value into the formula

F=\sqrt{1200^2+200^2+2\times1200\times200\cos90}

F=\sqrt{1200^2+200^2}

F= 1216.55\ N

The resultant of these forces is 1216.55 N.

(b). We need to calculate the direction of the resultant forces

Using formula of direction

\tan\alpha=\dfrac{F_{1}}{F_{2}}

Put the value into the formula

\alpha=\tan^{-1}(\dfrac{1200}{200})

\alpha=80.53^{\circ}

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(b).  The direction of the resultant forces is 80.53°.

4 0
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