Question

Silas tosses a football with an initial velocity of 10 ft/s from an initial height of 6 ft. What is the maximum height the ball will reach?

Answer 1

Sounds like a physics problem

basically we can simlpify it to this:
we toss something straight up with initial velocity 10ft/sec, assuming gravity kicks in, what is max height?

we can use the kinematic equation $v_{f}^2=v_{0}^2+2ad$
$v_f$ is final velocity
$v_0$ is initial velocity
a is acceleration due to gravity
d=distance traveled

if we say he tosses it straight up then when it  reaches max height, $v_f=0$
and $v_0=10 \frac{ft}{s}$

and we know that $a=-32.174 \frac{ft}{s^2}$

so solving for d

$v_{f}^2=v_{0}^2+2ad$
$v_{f}^2-v_{0}^2=2ad$
$\frac{v_{f}^2-v_{0}^2}{2a}=d$
plug the numbers in

$\frac{(0)^2-(10 \frac{ft}{s})^2}{2(-32.174 \frac{ft}{s^2})}=d$
$1.5540498539193137315845092310561 ft=d$

we add that to the initial 6ft
so total of 7.5540498539193137315845092310561 ft max height
about 7.6ft