Answer:
21N
Step-by-step explanation:
M. A = WORK OUTPUT ÷ WORK INPUT
Where M. A = 3.5 AND WORK OUTPUT = 75N
WORK INPUT = WORK(FORCE) OUTPUT ÷ M. A
= 75 ÷ 3.5 = 21.428
THEREFORE FORCE THE NUTCRACKER APPLIES TO THE WALNUT = 21.428 = Approx as 21N
Given: 75N force on nutcracker, 3.5 force on walnut
Using formula M. A = WORK OUTPUT ÷ WORK INPUT where M. A is not given W. O = 75N and W. I = 3.5N
75÷ 3.5 = 21N
Answer:
Step-by-step explanation:
tan30=oposite/adjucent side
1/1.732=30/adjectent side
adjectent side=30*1.732
adjecent side=51.96m.
Answer:
The answer in the procedure
Step-by-step explanation:
we have
x+2y > 6
Isolate the variable y
y > -0.5x+3
The solution of this inequality is the shaded area above the dashed line
The equation of the dashed line is y=-0.5x+3
The slope of the dashed line is negative (m=-0.5)
The y-intercept of the dashed line is 3 (value of y when the value of x is equal to zero)
The x-intercept of the dashed line is 6 (value of x when the value of y is equal to zero)
Plot the intercepts to draw the dashed line and shaded the area above the dashed line
see the attached figure
Answer:
GOOD LUCK TO HIM AND YOU!! YOU GOT THIS!!! Be sure to have fun though.
Answer:
y=-1/3-5
Step-by-step explanation:
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