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goldenfox [79]
2 years ago
14

Mode and median mean and range of 14,19,16,13,16,14

Mathematics
1 answer:
valentinak56 [21]2 years ago
5 0
Mean = 15 1/3
Median = 15
Mode = 14,16
Range = 6
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Which graph shows a function that always had a negative rate of change?
oee [108]

Answer: 2nd one is the right one

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3 years ago
solve this math problem. Estimate it by giving whole number. Show working also. (ESTIMATE, NOT WORK OUT) :)​
pentagon [3]

Answer:

(a) 11.

(b) 5.

Step-by-step explanation:

(a)√124:

11*11 = 121 so an estimate is 11.

(b) ∛124

5*5*5 = 125

So an estimate is 5.

5 0
2 years ago
The University of Montana ski team has thirteen entrants in a men's downhill ski event. The coach would like the first, second,
sleet_krkn [62]

Answer:

1716 ways

Step-by-step explanation:

Given that :

Number of entrants = 13

The number of ways of attaining first, second and third position :

The number of ways of attaining first ; only 1 person can be first ;

Using permutation :

nPr = n! ÷(n-r)!

13P1 = 13! ÷ 12! = 13

Second position :

We have 12 entrants left :

nPr = n! ÷(n-r)!

12P1 = 12! ÷ 11! = 12

Third position :

We have 11 entrants left :

nPr = n! ÷(n-r)!

11P1 = 11! ÷ 10! = 11

Hence, Number of ways = (13 * 12 * 11) = 1716 ways

8 0
2 years ago
Use a graphing calculator to graph f(x) = x+cos(kx). Use calculus to determine which values of k lead to a function with no loca
nataly862011 [7]

Answer:

Below, you can see the graph of the function:

f(x) = x + cos(k*x)

for different values of k, as follows:

red: k = 1

green: k = 2

orange: k = 0.

Now let's find the values of k such that our function does not have local maxima nor local minima.

First, remember that for a given function f(x), the local maxima or minima points are related to the zeros of the first derivate of f(x).

This means that if:

f'(x0) = 0.

Then x0 is a maxima, minima or an inflection point.

Then if a function is such that the f'(x) ≠ 0 , ∀x, then this function will not have local maxima nor minima.

Now we have:

f(x) = x + cos(k*x)

then:

f'(x) = 1  - k*sin(k*x)

This function will be zero when:

1 = k*sin(k*x)

1/k = sin(k*x)

now, remember that -1 ≤ sin(θ) ≤ 1

then if 1/k is smaller than -1, or larger than 1, we will not have zeros.

And this will happen if -1 < k < 1.

7 0
2 years ago
4(PX+1)=64 what is the value of x in terms of p and what is the value of x when p is -5 ?
Oksana_A [137]

Answer:

x = -3

Step-by-step explanation:

4(PX+1)=64\\\\p= -5

Substitute -5 for p in the given equation and solve

4(-5(x)+1)=64\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\frac{4\left(-5x+1\right)}{4}=\frac{64}{4}\\\\Simplify\\-5x+1=16\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\-5x+1-1=16-1\\\\Simplify\\-5x =15\\\\\mathrm{Divide\:both\:sides\:by\:}-5\\\frac{-5x}{-5}=\frac{15}{-5}\\\\Simplify\\x = -3

4 0
2 years ago
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