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AnnZ [28]
3 years ago
9

What is the length of the hypotenuse? Check my answer?

Mathematics
1 answer:
garik1379 [7]3 years ago
8 0
Yes 14 * sqrt2 is correct.
In a 45-45-90 triangle the ratio of the hypotenuse to the leg is sqrt 2
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scZoUnD [109]

Answer:

18.87 square cm.

Step-by-step explanation:

The area of the rectangle will be (4 + 4) * 4, since the length of the rectangle would be the diameter of the circle, and the width of the rectangle would be the radius. (4 + 4) * 4 = 8 * 4 = 32 square cm.

Then, we can calculate the area of the semicircle. The area of a circle is pi * r^2, so the area of a semicircle will be half of that. pi * (4^2) / 2 = pi * 16 / 2 = 8pi. 8 * 3.14159265 = 25.1327412 square cm.

The shaded area of the middle of the shape will then be 32 - 25.1327412 = 6.8672588 square cm.

The two triangles will have the same area. Their bases will be 14 minus the diameter of the circle, then divide that by 2 to get each separate base. 14 - 8 = 6 / 2 = 3. The heights of the triangles will be the radius of the circle, or 4 cm.

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6.8672588 + 12 = 18.8672588, or 18.87 square cm.

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