All categories

3 years ago

What is the area of a parallelogram if the coordinates of its vertices are (0, -2), (3, 2), (8, 2), and (5, -2)?

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

4 0

Answer:

The area of the parallelogram is 20 unit²

Step-by-step explanation:

We have that the area of a parallelogram = Base length, l × Height, h

The length of the base, l = √((5 - 0)² + (-2 - (-2))²) = 5

Given that the base of the parallelogram is parallel with to the x-axis, we have that the height is the difference between the a higher and a lower y-coordinate as follows;

h = y₃ - y₁ = 2 - (-2) = 2 + 2 = 4

Therefore, the area of the parallelogram, A = l × h = 4 × 5 = 20 unit².

You might be interested in

What is this expression in factored form?<br> x^2+13x+42

Allushta [10]

Answer and explanation:

$x^{2} + 13x + 42$

(x + 6)(x + 7)

List the multiples of 42

42: 1 2 3 6 7 14 21 42

Then see which of the multiples add up to 13

1 x 42 = 42 --> 1 + 42 $\neq$ 13

2 x 21 = 42 --> 2 + 21 $\neq$ 13

3 x 14 = 42 --> 3 + 14 $\neq$ 13

6 x 7 = 42 --> 6 + 7 = 13

4 0

3 years ago

What is subtraction?

Mazyrski [523]

Wen you deduct an amount from something

5 0

3 years ago

Read 2 more answers

I need the answer !!!

bonufazy [111]

I'm guessing you are looking for the answer on the first question, because I cannot read the rest of the second one lol.
So start with the volume of cone formula: V=3.14(5)^2 (6/3)
157.08
157
H is the answer

4 0

2 years ago

**MARKING BRAINLIEST PLEASE HELP**

Annette [7]

Answer:

1, 50.3

Step-by-step explanation:

the second part for question two could be anywhere from 50.1-50.4

3 0

2 years ago

A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed

PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

$\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}}$ ,

where $\sigma$ =population standard deviation.

$\overline{x}$ = sample mean

n= sample size

z* = Two-tailed critical z-value.

Given : $\sigma= 20$

n= 42

$\overline{x}=759$

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

$759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)$

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

3 0

3 years ago