Answer:
1/529
Step-by-step explanation:
![23^{-2}\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\23^{-2}=\frac{1}{23^2}\\\\23^2=529\\\\=\frac{1}{529}](https://tex.z-dn.net/?f=23%5E%7B-2%7D%5C%5C%5C%5C%5Cmathrm%7BApply%5C%3Aexponent%5C%3Arule%7D%3A%5Cquad%20%5C%3Aa%5E%7B-b%7D%3D%5Cfrac%7B1%7D%7Ba%5Eb%7D%5C%5C23%5E%7B-2%7D%3D%5Cfrac%7B1%7D%7B23%5E2%7D%5C%5C%5C%5C23%5E2%3D529%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B529%7D)
Answer:
0.03125 inches 1 hour is the anwser
this also involves the conversion factor
hope this helps!!
Answer:
q=10
Step-by-step explanation:
-10+10q=9q
-10=-q
q=10
Answer:
Either one of these.
Step-by-step explanation:
volumepile=1/3 (PI r^2)h
but r=h/2, so
volume=1/12 PI h^3
dv/dt=10 ft^3/min
but dv/dt=1/12 PI 3h^2 dh/dt
solve for dh/dt
This assumes you mean by "altitude" the height. If you mean altitude as slant height, you have to adjust the fromula
_______________________________________________
given: r = h/2
V = (1/3)π r^2 h
= (1/3)π (h/2)^2 (h)
= (1/12) π h^3
dV/dt = (1/4)π h^2 dh/dt
for the given data ...
10 = (1/4)π(25)dh/dt
dh/dt = 10(4)/((25π) = 1.6/π feet/min
1/8x2 and 4x I had usa test prep