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Anna71 [15]
3 years ago
6

The forces acting on this object are _______ and the net force is ________ Balanced, 0 N Balanced, 10 N Unbalanced, 10 N Unbalan

ced, 0 N
Physics
2 answers:
blondinia [14]3 years ago
7 0
The first one is balanced 

the 2nd one is  0 N

i took the test 2 times and the first time i got it wrong but when i reviewed the test it was this awnser
Amanda [17]3 years ago
5 0
1st Blank Answer: Balanced   
2nd Blank Answer: 0n 

I took the test and got it right
I would appreciate a Brainliest...
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A disc of mass m slides with negligible friction along a flat surface with a velocity v. The disc strikes a wall head-on and bou
qwelly [4]

Answer:

-v/2

Explanation:

Given that:

  • a disc of mass m
  • Collides with the wall going through a sliding motion on on the plane smooth surface.
  • Upon rebounding from the wall its kinetic energy becomes one-fourth of the initial kinetic energy before collision.

<u>We know, kinetic energy is given as:</u>

KE_i=\frac{1}{2}. m.v^2

consider this to be the initial kinetic energy of the body.

<u>Now after collision:</u>

KE_f=\frac{1}{4}\times KE_i

KE_f=\frac{1}{4} \times \frac{1}{2}\times m.v^2

Considering that the mass of the body remains constant before and after collision.

KE_f=\frac{1}{2}\times m.(\frac{v}{2})^2

Therefore the velocity of the body after collision will become half of the initial velocity but its direction is also reversed which can be denoted by a negative sign.

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3 years ago
Identify the techniques used to try to locate extra solar (exo) planets
attashe74 [19]

Answer:

the doppler technique

Explanation:

The doppler technique was  an indirect method for finding extrasolar planets and brown dwarfs from radial-velocity measurements using observation of Doppler shifts in the spectrum of the planet's parent star.

8 0
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Achild is pulling a toy train along the floor by a piece of string.
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Contact- Frictional force (Needs to be rubbing against the toy for it to happen)
Non Contact- Probably…? Gravitational force (Doesn’t need to be touching for it to happen)
6 0
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How does mercury differ from other metals?(1 point)
faltersainse [42]

Answer:

It is not solid under normal conditions

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Please answer all the questions
Sever21 [200]

Answer:

<u>See Below for explanation and answers</u>

Explanation:

We are going to solve these problems using the formula:

W = mg

Where

W is weight in Newtons (N)

m is mass in (kg)

g is acceleration due to gravity

  • <u>Ex 1.</u>

g on earth is 9.8 m/s^2

So,

<u>Weight on Earth = mg = 45 * 9.8 = 441 N</u>

Mass doesn't change, so on Jupiter, Felicia's mass would be same.

<u>Mass on Jupiter = 45 kg</u>

The weight on Jupiter would change because of g changing to 25, so

<u>Weight on Jupiter = mg = 45 * 25 = 1125 N</u>

<u></u>

  • <u>Ex 2.</u>

Moon's g is 1/6th of earth, so it would be:

Moon g = (1/6)*9.8 = 1.63

Now,

On earth weight of backpack = mg = 1760

On moon weight would be = m(1/6 g) = 1760/6 = 293.33 N

A) <u>Backpack Weight on Moon = 293.33 N</u>

On moon, the mass would be same as earth, so lets calculate:

W = mg

293.33 = m (1.63)

m = 179.96 kg

B) <u>Mass of Backpack on Moon = 179.96 kg</u>

<u></u>

  • <u>1.</u>

Taking he is on earth with a weight of 1150 Newtons, his mass would be:

W = mg

1150 = m(9.8)

m = 117.35 kg

<u>Mass = 117.35 kg</u>

<u>Weight = 1150 N</u>

<u></u>

  • <u>2.</u>

g is Mars is 3.7

Weight on earth is 64 N

the g of Mars is  \frac{3.7}{9.8}=0.38 of the g on earth, so weight would go down by that factor.

<u>Weight of Melon on Mars = 64 * 0.38 = 24.32 N</u>

<u></u>

The mass would be (on Mars):

W = mg

24.32 = m (3.7)

m = 6.57 kg

<u>Mass of Melon on Mars = 6.57 kg</u>

3 0
3 years ago
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