<h2>
Answer:</h2>
1.77V
<h2>
Explanation:</h2>
The electromotive force voltage (E) in a cell, is related to the lost voltage (
) and the terminal voltage (
) as follows;
E = -
Where;
The lost voltage () is the product of the internal resistance (r) of the cell and current (I) in the cell. i.e
= I x r
<em>Substitute </em><em> = I x r into equation (i) as follows;</em>
E = - (I x r) ----------------------(ii)
<em>According to the question;</em>
E = 1.54V
I = 2.15A
r = 0.105Ω
<em>Substitute these values into equation(ii) as follows;</em>
1.54 = - (2.15 x 0.105)
1.54 = - (0.22575)
1.54 = - 0.22575
<em>Solve for </em><em>;</em>
= 1.54 + 0.22575
= 1.54 + 0.22575
= 1.77V
Therefore, the terminal voltage of the cell is 1.77V
The answer to this question is yes. It’s true
Answer:
a =( -0.32 i ^ - 2,697 j ^) m/s²
Explanation:
This problem is an exercise of movement in two dimensions, the best way to solve it is to decompose the terms and work each axis independently.
Break down the speeds in two moments
initial
v₀ₓ = v₀ cos θ
v₀ₓ = 5.25 cos 35.5
v₀ₓ = 4.27 m / s
= v₀ sin θ
= 5.25 sin35.5
= 3.05 m / s
Final
vₓ = 6.03 cos (-56.7)
vₓ = 3.31 m / s
= v₀ sin θ
= 6.03 sin (-56.7)
= -5.04 m / s
Having the speeds and the time, we can use the definition of average acceleration that is the change of speed in the time order
a = (
- v₀) /t
aₓ = (3.31 -4.27)/3
aₓ = -0.32 m/s²
= (-5.04-3.05)/3
= -2.697 m/s²
Answer:
Increase 9 times
Explanation:
We have Newton formula for attraction force between 2 objects with mass and a distance between them:
where 
is the gravitational constant. 
is the masses of the 2 objects. and R is the distance between them.
Since the force is inversely proportional to the distance squared, if it is reduced by 3 times, the gravitational force between them would increase by 
times
