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Aleksandr-060686 [28]
3 years ago
11

proton is accelerated to a speed of 0.93c, what is the 1. A proton has a mass of 1.673 x 10-27 kg. If the proton is accelerated

to a speed magnitude of the relativistic momentum of the proton? A. 6.2 x 10-17 kg. m/s B. 1.3 x 10-18 kg. m/s C. 4.7 x 10-19 kg. m/s D. 5.9 x 10-24 kg. m/s E. 1.8 * 10-18 kg . m/s
Physics
1 answer:
coldgirl [10]3 years ago
5 0

Answer : The correct option is, (B) 1.3\times 10^{-18}kg.m/s

Explanation : Given,

Mass of proton = 1.673\times 10^{-27}kg

Speed of proton = 0.93 c

Formula used for relativistic momentum of the proton is:

p=\frac{m_ov}{\sqrt{1-\frac{v^2}{c^2}}}

where,

p = relativistic momentum of the proton

m_o = mass of proton

v = speed of proton

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

p=\frac{(1.673\times 10^{-27}kg)\times (0.93c)}{\sqrt{1-\frac{(0.93c)^2}{c^2}}}

p=\frac{(1.55589\times 10^{-27}c)}{0.367}

p=\frac{(1.55589\times 10^{-27})\times (3\times 10^8)}{0.367}

p=1.272\times 10^{-18}kg.m/s\approx 1.3\times 10^{-18}kg.m/s

Therefore, the relativistic momentum of the proton is, 1.3\times 10^{-18}kg.m/s

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