Answer:
1.Free edge
2.Nail Root
3.Nail matrix
4.lunula
Note: The numbering coincides respectively with the dashes in the questions.
Explanation:
Free edge is the distal white nail ending.
Nail Root is the proximal part of the nail embedded in the skin.
Nail matrix is the actively growing part of the nail were the nail root thickens
Lunula the whitish semilunar area of the proximal end of the nail body it appears whitish because stratum basala obscures. the underlying blood vessels.
Answer:
The magnitude of the gravitational force acting on the lander on the surface of Mars is 512.46 N.
Explanation:
The Universal law of gravity is define as:
(1)
Where F is the gravitational force, G is gravitational constant, M is the mass of Mars, m is the mass of the lander and R is the radius of Mars.
Before replacing the values in equation 1 it is necessary to express the radius of mars in terms of meters:
R = ⇒ R =
Finally, equation 1 can be used:
Hence, the magnitude of the gravitational force acting on the lander on the surface of Mars is 512.46 N.
Edison's education is most unique and relevant.
1. The first teacher he had was his mother
2. He found vital lessons and was influenced greatly by the book of R.G. Parker called School of Natural Philosophy
3. Another educating piece he had was a book entitled The Cooper Union for the Advancement of Science and Art
His style of learning was though reading books on a variety of subjects, a self-educating environment that fosters independent learning which can be useful through his life.
Answer:
A. 243 N
Explanation:
Friction is the force that opposes the relative motion between systems that are in contact.
This friction force that opposes the motion of the oak chest across the oak surface will be equal and opposite to that exerted by the woman.
First find the normal force which is the force that would point directly upwards to support weight of the block.
Normal force, N= mg where m is the mass of the chest and g is the acceleration due to gravity.
Given m=40 kg and g=9.80 m/s²
N force=40×9.80 =392N
Then find the force of friction which is given by the formula;
<em>F=μN where μ is friction coefficient for the oak chest and N is the normal force on the chest</em>
Given <em>μ</em>=0.620 and N force = 392 N then it will be;
F=0.620× 392 =243.04 N
Answer : 243 N
Answer:
A: They produce a real image.
Explanation:
The images formed on the retina of the eye for a normal visibility must always be real.
Only a real image can be physically projected on any physical object whereas the virtual images are visible due to reflections.
- The nearsightedness is corrected with the help of a concave lens since it is the condition of the eye lens remaining thick and curved to converge the rays entering the eyes after a shorter distance which results in their image formation even before the retinal surface so to initially diverge them a bit so that they converge on the retinal surface and form the image there we use concave lens. Vice-versa of the above justification in the case of farsightedness.