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inysia [295]
3 years ago
6

A bullet is fired vertically upward a velocity of 80m/s to what height will the bullet rise above the point of projection​

Physics
1 answer:
frozen [14]3 years ago
3 0

Answer:

The bullet will rise 320 meters above the point of projection.

Explanation:

Assuming that air friction is negligent we can use the kinematic equation:

v_{2} ^2=v_{1} ^2+2(-a)d\\0\frac{m^2}{s^2} =6400\frac{m^2}{s^2} +2(-10\frac{m}{s^2} )d\\-6400\frac{m^2}{s^2} =(-20\frac{m}{s^2}) d\\320m=d

*acceleration is negative (-a) as it is acting in the opposite direction of the motion of the bullet.*

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During which two time intervals does the particle undergo equal displacement?
san4es73 [151]

Answer:

BC and DE

Explanation:

In the given figure, the velocity time graph is shown. We know that the area under v-t curve gives the displacement of the particle.

Area under AB, d_1=\dfrac{1}{2}\times 2\times 10=10\ m

Area under BC, d_2=\dfrac{1}{2}\times 2\times 4=4\ m

Area under CD, d_3=\dfrac{1}{2}\times 2\times 7=7\ m

Area under DE, d_4=\dfrac{1}{2}\times 2\times 4=4\ m

Area under EF, d_5=\dfrac{1}{2}\times 2\times 3=3\ m

So, form above calculations it is clear that, during BC and DE undergo equal displacement. Hence, the correct option is (c) "BC and DE = 4 meters".

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2 years ago
What is the atomic mass of an element?
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faust18 [17]

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Easy one here pls help thanks so much
Kisachek [45]
The answer is B. Nutrients.
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