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inysia [295]
3 years ago
6

A bullet is fired vertically upward a velocity of 80m/s to what height will the bullet rise above the point of projection​

Physics
1 answer:
frozen [14]3 years ago
3 0

Answer:

The bullet will rise 320 meters above the point of projection.

Explanation:

Assuming that air friction is negligent we can use the kinematic equation:

v_{2} ^2=v_{1} ^2+2(-a)d\\0\frac{m^2}{s^2} =6400\frac{m^2}{s^2} +2(-10\frac{m}{s^2} )d\\-6400\frac{m^2}{s^2} =(-20\frac{m}{s^2}) d\\320m=d

*acceleration is negative (-a) as it is acting in the opposite direction of the motion of the bullet.*

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4. For a series of experimentally measured values give the definition of (a) average or mean value (b) the deviation from the me
Naya [18.7K]

Answer:

a)   x_average = ∑ x_{i} / n , b) Δx_{i} = x_{i} –x_average,

d) σ = √(1/n-1  ∑ Dx_{i}² )

Explanation:

Some definitions are requested

a) the average value is the sum of all the values ​​divided by the number of them, if the uncertainties are random, this is the closest value to the real one

       x_average = ∑ x_{i} / n

b) The deviation from the mean value or absolute error is the measured value minus the average value

       Δx_{i} = x_{i} –x_average

c) is the average value of the deviations

        Δx_average = ∑ Δx_{i} / n

d) It is a measure of the dispersion of the values ​​with respect to their average value, it takes the worst of all cases, widely used for large numbers of data

          σ = √(1/n-1  ∑ Dx_{i}² )

Experimental results should be given as follows

  Average value ± uncertainty and the standard deviation

  (x_average + - Δx_average)

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2 years ago
Find the slope of the line that passes through the points (-1, 3) and (2, -5)-
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Answer:

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Explanation:

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The most common units for expressing the density of a substance are the g/cm3.
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3 years ago
A parallel-plate air capacitor is made from two plates 0.190 m square, spaced 0.770 cm apart. It is connected to a 120 V battery
Naddik [55]

Answer:

aaksj

Explanation:

a) the capacitance is given of a plate capacitor is given by:

C = \epsilon_0*(A/d)

Where \epsilon_0 is a constant that represents the insulator between the plates (in this case air, \epsilon_0 = 8.84*10^(-12) F/m), A is the plate's area and d is the distance between the plates. So we have:

The plates are squares so their area is given by:

A = L^2 = 0.19^2 = 0.0361 m^2

C = 8.84*10^(-12)*(0.0361/0.0077) = 8.84*10^(-12) * 4.6883 = 41.444*10^(-12) F

b) The charge on the plates is given by the product of the capacitance by the voltage applied to it:

Q = C*V = 41.444*10^(-12)*120 = 4973.361 * 10^(-12) C = 4.973 * 10^(-9) C

c) The electric field on a capacitor is given by:

E = Q/(A*\epsilon_0) = [4.973*10^(-9)]/[0.0361*8.84*10^(-12)]

E = [4.973*10^(-9)]/[0.3191*10^(-12)] = 15.58*10^(3) V/m

d) The energy stored on the capacitor is given by:

W = 0.5*(C*V^2) = 0.5*[41.444*10^(-12) * (120)^2] = 298396.8*10^(-12) = 0.298 * 10 ^6 J

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2 years ago
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