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azamat
3 years ago
10

Give an example of an energy conversion that produces an enwanted from of energy

Physics
1 answer:
stira [4]3 years ago
4 0
An example of an energy conversion that produces an unwanted form of energy is mixing acids with water. 
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A 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. What happens t
olya-2409 [2.1K]

The answer is C as there is more force on the left side ( excess of 5 N) which therefore pushed it to the right with a force of 5 N!


8 0
3 years ago
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Consider two isolated, charged conducting spheres: a large sphere and a second smaller sphere with a radius 6 times smaller than
Troyanec [42]

Let the bigger sphere be sphere 1 and the let the smaller sphere be sphere 2. Rest of the answer is in the picture.

4 0
3 years ago
A simple generator has a square armature 9.0 cm on a side. The armature has 95 turns of 0.59-mm-diameter copper wire and rotates
Marrrta [24]

Answer:

f = 3.102 Hz

Explanation:

In this case you have that the required voltage is the maximum induced emf produced by the rotating generator.

In order to calculate the frequency of rotation of the generator that allows one to obtain 12.0V you use the following formula:

emf_{max}=NBA\omega    (1)

N: turns of the armature = 95

B: magnitude of the magnetic field = 0.800T

A: area of the square armature = (9.0cm)^2 = (0.09m)^2 = 8.1*10^-3 m^2

emf_max = 12.0V

w: angular frequency

you solve the equation (1) for w:

\omega=\frac{emf_{max}}{NBA}=\frac{12.0V}{(95)(0.800T)(8.1*10^{-3}m^2)}\\\\\omega=19.49\frac{rad}{s}

Then, the frequency is:

f=\frac{\omega}{2\pi}=\frac{19.49rad/s}{2\pi}=3.102Hz

7 0
3 years ago
A chemical reaction that has the general formula of AB + C → CB + A is best classified as a reaction.
MissTica

Answer:

Single replacement

Explanation:

A reaction in which one element replaces a similar element is called single replacement.  In this case, C is replacing A.

7 0
4 years ago
Read 2 more answers
A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of
Gekata [30.6K]

Answer:

a) P=2450\ Pa

b) \delta h=23.162\ cm

Explanation:

Given:

height of water in one arm of the u-tube, h_w=25\ cm=0.25\ m

a)

Gauge pressure at the water-mercury interface,:

P=\rho_w.g.h_w

we've the density of the water =1000\ kg.m^{-3}

P=1000\times 9.8\times 0.25

P=2450\ Pa

b)

Now the same pressure is balanced by the mercury column in the other arm of the tube:

\rho_w.g.h_w=\rho_m.g.h_m

1000\times 9.8\times 0.25=13600\times 9.8\times h_m

h_m=0.01838\ m=1.838\ cm

<u>Now the difference in the column is :</u>

\delta h=h_w-h_m

\delta h=25-1.838

\delta h=23.162\ cm

7 0
3 years ago
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