When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute:
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025= 0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
= 0.0075 * 63.546 =0.477 g
(C) NaNO3
Cant be A,B,orD not suitable
Answer:
1.Balance the equation.
2.Convert units of a given substance to moles.
3.Using the mole ratio, calculate the moles of substance yielded by the reaction.
4.Convert moles of wanted substance to desired units.
Explanation:
Answer:
An atom of ¹¹⁸Xe contains 64 neutrons.
Explanation:
Number of Protons:
The number of protons present in any atom are equal to the atomic number of that particular atom. Hence, as the atomic number of Xenon is 54 therefore, it contains 54 protons.
Number Neutrons:
The number of neutrons present in atom are calculated as,
# of Neutrons = Atomic Mass - # of protons
As given,
Atomic Mass = 118
# of Protons = 54
So,
# of Neutrons = 118 - 54
# of Neutrons = 64
Answer:
It becomes an ion
Explanation:
The element it took from becomes a positive ion
And chlorine becomes a negative ion