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Whitepunk [10]
3 years ago
14

Latoya performs an experiment using the lab equipment shown. Which two properties is Latoya most likely measuring?

Chemistry
2 answers:
spayn [35]3 years ago
5 0

Answer: Volume and temperature

Explanation:

galina1969 [7]3 years ago
5 0

Answer:

volume and temperature

Explanation:

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Explanation:

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The amount of kinetic energy required for the molecules to break free of the intermolecular forced in the liquid is raised because the other ones don’t make sense
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A solution that has a high concentration of hydrogen ions has what type of pH?
Degger [83]

<u>Given information:</u>

A solution with a high H+ ion concentration

<u>To determine:</u>

The nature of pH of such a solution

<u>Explanation:</u>

pH is a measure of the H+ ion concentration in a given solution. Lower the pH higher will be the H+ concentration and the solution is termed acidic. In contrast, if the pH is higher the H+ concentration will be lower and the solution is basic.

Mathematically,

pH = -log[H+]

[H+] = 10^{-pH}

pH = 2; [H+] = 10⁻²M

pH = 7; [H+] = 10⁻⁷M

pH = 13; [H+] = 10⁻¹³M

pH = 14; [H+] = 10⁻¹⁴M

Ans: (a)

Thus, the highest concentration of H+ ions is for a solution of pH = 2

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2 years ago
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What is the equilibrium constant expression for the given system?
artcher [175]
<h3>Answer:</h3>

\displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • States of matter

<u>Kinetics</u>

  • Rate Laws

<u>Equilibrium</u>

  • Equilibrium Reactions RxN ⇄
  • Equilibrium Constants
  • Equilibrium Expression: \displaystyle K = \frac{[Producst]^{coefficients}}{[Reactants]^{coefficients}}
<h3>Explanation:</h3>

*Note: Only gases and liquids affect equilibrium

<u>Step 1: Define</u>

[RxN - Balanced] 2H₂O (g) ⇄ 2H₂ (g) + O₂ (g)

<u>Step 2: Identify</u>

[Reactant] H₂O

  • Coefficient of 2

[Product] H₂

  • Coefficient of 2

[Product] O₂

  • Coefficient of 1

<u>Step 3: Write K Expression</u>

  1. Substitute:                                                                                                       \displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}
5 0
2 years ago
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