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Whitepunk [10]
3 years ago
14

Latoya performs an experiment using the lab equipment shown. Which two properties is Latoya most likely measuring?

Chemistry
2 answers:
spayn [35]3 years ago
5 0

Answer: Volume and temperature

Explanation:

galina1969 [7]3 years ago
5 0

Answer:

volume and temperature

Explanation:

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What is the precipitate for CuSO4+NaOH<br> (Balancing Equations)
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CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

Explanation:

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How many atoms are in 175.8 grams of Hg?
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5.22*22^3 should be the answer
5 0
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At STP how many moles or helium would occupy a volume of 12 liters?
butalik [34]
1 mole ------------- 22.4 L ( at STP )
?? mole ---------- 12 L

12 x 1 / 22.4 => 0.5357 moles

hope this helps! 
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3 years ago
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3 years ago
Collected data consists of:
san4es73 [151]

The number of moles of the magnesium (mg) is 0.00067 mol.

The number of moles of hydrogen gas is 0.0008 mol.

The volume of 1 more hydrogen gas (mL) at STP is 22.4 L.

<h3>Number of moles of the magnesium (mg)</h3>

The number of moles of the magnesium (mg) is calculated as follows;

number of moles = reacting mass / molar mass

molar mass of magnesium (mg) = 24 g/mol

number of moles = 0.016 g / 24 g/mol = 0.00067 mol.

<h3>Number of moles of hydrogen gas</h3>

PV = nRT

n = PV/RT

Apply Boyle's law to determine the change in volume.

P1V1 = P2V2

V2 = (P1V1)/P2

V2 = (101.39 x 146)/(116.54)

V2 = 127.02 mL

Now determine the number of moles using the following value of ideal constant.

R = 8.314 LkPa/mol.K

n = (15.15 kPa x 0.127 L)/(8.314 x 290.95)

n = 0.0008

<h3>Volume of 1 mole of hydrogen gas at STP</h3>

V = nRT/P

V = (1 x 8.314 x 273) / (101.325)

V = 22.4 L

Learn more about number of moles here: brainly.com/question/13314627

#SPJ1

7 0
1 year ago
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