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Wewaii [24]
3 years ago
15

What is the area of the rectangle below?

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:

52 if im wrong sorry :(

Step-by-step explanation:

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Instructions: Select the correct answer from each drop-down menu. ∆ABC rotates around point D to create ∆A′B′C′. Based on t
fgiga [73]
The answer to the first part is (4,1).
The answer to the second part is (11,2).
7 0
4 years ago
Read 2 more answers
8+30\2+4=27 put parentheses so it can equal 23 and 13
zhannawk [14.2K]

Answer:

correct anwer=27

Step-by-step explanation:

the anwer for this equation comes out to be 27. As simple as it becomes on applying paranthesis to this equation therefore we get

8+(30/2)+4=27

we need to apply the paranthesis using the method of BODMAS.

which favours division over addition.

therefore,correct anwer is 27 and not 13

6 0
3 years ago
Mark works at the mall 3 hours on Friday and 5 hours on Saturday. He gets a
zvonat [6]

Answer:

$7.50

Step-by-step explanation:

3 hours + 5 hours = 8 hours

8 hours = $85 (total) - $25 (allowance)

8 hours = $60 (money earned from work)

1 hour = $60 ÷ 8 (hours he worked)

1 hour = $7.50

5 0
3 years ago
Which expression is equivalent to 2x2 + (4x - 6x2) + 9 - (6x + 3)?​
Troyanec [42]

Answer:

-4x^2-10x+6

Step-by-step explanation:

I am going to assume the (Something)x2 means (Something)x^2. Then, the expression is 2x^2-6x^2\\+4x-6x+9-3=-4x^2-10x+6

4 0
3 years ago
Read 2 more answers
Suppose that contamination particle size (in micrometers) canbe modeled as
asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1

a) probability density function.

\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1

Thus, it is a probability density function.

b) cumulative distribution function.

P(X

c) mean of the distribution

\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2

d) probability that the size of random particle will be less than 5 micrometers

P(X

4 0
3 years ago
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