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2 years ago

Determine the current through each of the LEDs in the circuits below. Which LED will be

Mathematics

1 answer:

Anika [276]2 years ago

8 0

a. $I = 6. 1$ × $10^-4$ A

b. $I = 2. 6$ × $10^-3$ A

c. $I = 0. 04$ A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

$I = \frac{12}{19700}$

$I = 6. 1$ × $10^-4$ A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

$I = \frac{12}{4700}$

$I = 2. 6$ × $10^-3$ A

C. V= 12V

1/R = $\frac{1}{750} + \frac{1}{1200} + \frac{1}{950 }$ = $3. 22$ × $10^-3$

R = $\frac{1}{3. 22 * 10 ^-3}$ = 310. 56 Ω

$I = \frac{12}{310. 56}$

$I = 0. 04$ A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

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Please answer right awat

likoan [24]

<u>Answer:</u>

The correct answer option is 0.2.

<u>Step-by-step explanation:</u>

We are given that there are 3 red marbles and 3 green marbles in an opaque bag.

If two marbles are chosen one after one without replacement, we are to find the probability of getting both green marbles.

P (1st green marble) = $\frac { 3 } { 6 }$

P (2nd green marble) = $\frac { 2 } { 5 }$

P (both green marbles) = $\frac { 3 } { 6 } \times \frac { 2 } { 5 }$ = 0.2

6 0

3 years ago

if the area of a rectangle is expressed as x^4 - 9y^2, then the product of the length and the width of the rectangle could be ex

kvasek [131]

Answer:the product of the length and the width of the rectangle could be expressed as

(x^2 - 3y)(x^2 + 3y)

Step-by-step explanation:

If the area of a rectangle is expressed as x^4 - 9y^2, we would determine the dimensions by simplifying the given expression. The simplified expression becomes

(x^2 - 3y)(x^2 + 3y)

Let us check by multiplying each term in one parenthesis by each term in the other parenthesis to get the given expression. It becomes

(x^2 - 3y)(x^2 + 3y) = x^4 + 3x^2y - 3x^2y - 9y^2 = x^4 - 9y^2

6 0

3 years ago

what is the simplified form of the following expression? Assume X 0 and y 0. 2(^4 sqrt 16 x) -2(^4 sqrt 2y )+3 (^4 sqrt 81x ) -4

eduard

For this case we have the following expression:

$2(\sqrt[4]{16x})-2(\sqrt[4]{2y})+3(\sqrt[4]{81x})-4(\sqrt[4]{32y})$

Rewriting the numbers within the roots we have:

$2(\sqrt[4]{2*2*2*2x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3*3*3*3x})-4(\sqrt[4]{2*2*2*2*2y})$

Then, by properties of powers we have:

$2(\sqrt[4]{2^4x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3^4x})-4(\sqrt[4]{2^42y})$

Then, by radical properties we have:

$2(2\sqrt[4]{x})-2(\sqrt[4]{2y})+3(3\sqrt[4]{x})-4(2\sqrt[4]{2y})$

Rewriting the expression we have:

$4\sqrt[4]{x}-2\sqrt[4]{2y}+9\sqrt[4]{x}-8\sqrt[4]{2y}$

Finally, adding similar terms we have:

$(4+9)\sqrt[4]{x}-(2+8)\sqrt[4]{2y}$

$13\sqrt[4]{x}-10\sqrt[4]{2y}$

Answer:

The simplified form of the expression is:

$13\sqrt[4]{x}-10\sqrt[4]{2y}$

7 0

3 years ago

Read 2 more answers

A spinner had 5 equal sections, labeled A through E. After 100 spins, the spinner had landed on section A a total of 45 times.

arsen [322]

Where’s the question?

6 0

3 years ago

Read 2 more answers

200 ml of milk

Black_prince [1.1K]

A ratio shows us the number of times a number contains another number. The amount barely needed for 300 ml of milk is 45 grams.

<h3>What is a Ratio?</h3>

A ratio shows us the number of times a number contains another number.

The need for barley in 200 ml of milk is 30 grams, therefore, the need for barley in 1 ml of milk can be written as,

Need of barely in 1 ml of milk = 30/200

Now, the amount of barely that will be needed for 300 ml of milk will be,

The amount of barely in 300 ml of milk = (30/200)×300 = 45 grams.

Hence, the amount barely needed for 300 ml of milk is 45 grams.

Learn more about Ratios:

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4 0

2 years ago