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LUCKY_DIMON [66]
3 years ago
12

Jamie has 4 apples and 6 bananas. Each apple cost 0.75 and each banana cost 0.6” write an expression representing the total cost

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0
Hello!

4 x 0.75 + 6 x 0.6 = 6.6

Enjoy.
~Isabella
Lorico [155]3 years ago
5 0
(0.75*4) + (0.6*6) = 6.6

answer: 6.6
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Given that m 2 = 56 in the diagram what is m 8<br>A 134<br>B 66<br>C 124 <br>D 56​
algol [13]
The answer is:
Letter B
5 0
2 years ago
3x^2(4x^3-2x^2+7x-4)
Lunna [17]

▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄

<h3>>> Given Question :</h3>

3x²(4x³ - 2x² + 7x - 4)

<h3>>> Required Solution :</h3>

12x⁵ - 6x⁴ + 21x³ - 12x²

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6 0
2 years ago
Need to know the area of the composite figure.
Deffense [45]

Answer:

  51 m^2

Step-by-step explanation:

The shaded area is the difference between the area of the overall figure and that of the rectangular cutout.

The applicable formulas are ...

  area of a triangle:

     A = (1/2)bh

  area of a rectangle:

     A = bh

  area of a trapezoid:

     A = (1/2)(b1 +b2)h

___

We note that the area of a triangle depends only on the length of its base and its height. The actual shape does not matter. Thus, we can shift the peak of the triangular portion of the shape (that portion above the top horizontal line) so that it lines up with one vertical side or the other of the figure. That makes the overall shape a trapezoid with bases 16 m and 10 m. The area of that trapezoid is then ...

  A = (1/2)(16 m + 10 m)(5 m) = 65 m^2

The area of the white internal rectangle is ...

  A = (2 m)(7 m) = 14 m^2

So, the shaded area is the difference:

  65 m^2 -14 m^2 = 51 m^2 . . . . shaded area of the composite figure

_____

<em>Alternate approach</em>

Of course, you can also figure the area by adding the area of the triangular "roof" to the area of the larger rectangle, then subtracting the area of the smaller rectangle. Using the above formulas, that approach gives ...

  (1/2)(5 m)(16 m - 10 m) + (5 m)(10 m) - (2 m)(7 m) = 15 m^2 + 50 m^2 -14 m^2

  = 51 m^2

7 0
3 years ago
Math inspection:who is right?
Pavel [41]

Answer:

I don't know

Step-by-step explanation:

6 0
3 years ago
5 points
jonny [76]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{2}x-5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 2 and passes through (4 , -3)

(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y+3=2x-8\implies y=2x-11

5 0
2 years ago
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