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fiasKO [112]
3 years ago
10

Excitation and relaxation of electrons in what element are responsible for most of the light reaching Earth from the Sun? A) Arg

on B) Helium C) Hydrogen D) Iron
Chemistry
2 answers:
vfiekz [6]3 years ago
7 0
The answer here is B: Helium.

As many stars, the sun is largely composed of hydrogen and helium. The sun is able to give off radiant energy through the nuclear fusion process. This involves the process by which hydrogen isotopes fuses to create one helium atom and then creates radiant energy that travels to Earth.


Advocard [28]3 years ago
5 0

the correct answer is c) hydrogen

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Laurie is moving a dresser with a mass of 250kg. She does 126 J of work with a force of 14 N. How far does she move the dresser?
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7 0
3 years ago
A class of substances known as __________ are used for their medicinal properties.
Misha Larkins [42]

Answer: Alkaloids

A class of substances known as alkaloids are used for their medicinal properties.

Explanation:

Alkaloids are small but complex organic substances with at least one nitrogen atom in its ring structure. Hence, they have strong basic properties, and are produced in naturally by some plants.

Examples of alkaloids and their medicinal properties are as follows:

- caffeine, used in certain drug and drinks to stimulate the nervous system

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3 years ago
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nordsb [41]

Answer:

-304.1

I had this question and that’s what I got

6 0
3 years ago
For a particular reaction at 235.8 °C, ΔG=−936.92 kJ/mol , and ΔS=513.79 J/(mol⋅K) . Calculate ΔG for this reaction at −9.9 °C.
Rudik [331]

Answer:

-138.9 kJ/mol

Explanation:

Step 1: Convert 235.8°C to the Kelvin scale

We will use the following expression.

K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K

Step 2: Calculate the standard enthalpy of reaction (ΔH°)

We will use the following expression.

ΔG° = ΔH° - T.ΔS°

ΔH° = ΔG° / T.ΔS°

ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K

ΔH° = -3.583 kJ (for 1 mole of balanced reaction)

Step 3: Convert -9.9°C to the Kelvin scale

K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K

Step 4: Calculate ΔG° at 263.3 K

ΔG° = ΔH° - T.ΔS°

ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K

ΔG° = -138.9 kJ/mol

8 0
3 years ago
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