<h3>
Answer:</h3>
M= Cu
<h3>
Explanation:</h3>
From the question;
Mass of metal carbonate = 1.056 g
Mass of CO₂ = 0.376 g
We are required to identify the metal M in the carbonate
The equation for the combustion of the carbonate;
MCO₃(s) + heat → MO(s) + CO₂(g)
<h3>Step 1: Calculating the number of moles of CO₂</h3>
Moles = Mass ÷ molar mass
Molar mass CO₂ = 44.01 g/mol
Moles = 0.376 g ÷ 44.01 g/mol
= 0.00854 Moles
<h3>Step 2: Determining the moles of MCO₃ </h3>
From the equation;
1 mole of the metal carbonate decomposes to yield 1 mole CO₂
Therefore; Mole ratio of MCO₃ : CO₂ = 1 : 1
Hence; Moles of MCO₃ = 0.00854 moles
<h3>Step 3: Determining the molar mass of MCO₃</h3>
Moles of MCO₃ = 0.00854 moles
Mass of the carbonate = 1.056 g
But;
Molar mass = Mass ÷ moles
= 1.056 g ÷ 0.00854 moles
= 123.65 g/mol
<h3>Step 4: Atomic mass of the metal </h3>
The molar mass of metal carbonate = 123.65 g/mol
Atomic mass of carbon = 16
Atomic mass of oxygen = 12.01
Therefore;
123.65 g = M + 12.01 + (16 ×3)
M = 63.64 g
The atomic mass of M is 63.64 approximately the same as that of copper.
Atomic mass of Cu is 63.546
Therefore, identity of M is Cu
