Question

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and hotdogs and made $420. How many of each did they sell?
What solution is reasonable?
Question 3 options:


200 hamburgers and 50 hotdogs


50 hamburgers and 200 hotdogs


120 hamburgers and 180 hotdogs


100 hamburgers and 180 hotdogs

I think the answer is 120 hamburgers and 180 hotdogs ,but I'm not sure.Thanks to whoever helps me .

Answer 1

120 hamburgers and 180 hot dogs.

Answer 2

Answer: 120 hamburgers and 180 hotdogs

Step-by-step explanation:

Let 'x' be the number of hamburgers and 'y' be the number of hotdogs sold.

Then, the total number of hamburgers and hotdogs sold on friday will be given by :_

$x+y=300.....................(1)$

On the basis of their cost, the total cost will be:-

$2x+y=420..............................(2)$

Subtract (1) from (2), we get

$x=120$

Substitute the value of x in  (1), we get

$120+y=300\\\Rightarrow y=300-120\\\Rightarrow y=180$

Hence, they sold 120 hamburgers and 180 hotdogs.