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Anni [7]
4 years ago
11

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and h

otdogs and made $420. How many of each did they sell?
What solution is reasonable?
Question 3 options:


200 hamburgers and 50 hotdogs


50 hamburgers and 200 hotdogs


120 hamburgers and 180 hotdogs


100 hamburgers and 180 hotdogs

I think the answer is 120 hamburgers and 180 hotdogs ,but I'm not sure.Thanks to whoever helps me .
Mathematics
2 answers:
vladimir2022 [97]4 years ago
5 0
120 hamburgers and 180 hot dogs.
mixer [17]4 years ago
3 0

Answer: 120 hamburgers and 180 hotdogs

Step-by-step explanation:

Let 'x' be the number of hamburgers and 'y' be the number of hotdogs sold.

Then, the total number of hamburgers and hotdogs sold on friday will be given by :_

x+y=300.....................(1)

On the basis of their cost, the total cost will be:-

2x+y=420..............................(2)

Subtract (1) from (2), we get

x=120

Substitute the value of x in  (1), we get

120+y=300\\\Rightarrow y=300-120\\\Rightarrow y=180

Hence, they sold 120 hamburgers and 180 hotdogs.

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URGENT!!!!<br> Please add workings out
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Answer: 26.457 cm

Explanation:

First, the height of an equilateral triangle of side length a is:

h = \frac{\sqrt{3} }{2}*a

In this case, the side-length of the triangles is a = 10cm, then the height will be:

h = \frac{\sqrt{3} }{2}*10cm = 8.66cm

Now we can think on a triangle rectangle such that:

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The line we want to find, the line from A to F, is the hypotenuse.

One cathetus is a the height of the triangle, that comes down from point A, the length of this cathetus is 8.66cm

The other cathetus is equal to half the side length of the triangles (5cm) plus the segments BD and DF (of 10cm each)

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