Same would need to get at least a 95% on the next test, if he would like to receive a total average of an 80%
(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when
and
, and because the velocity function is continuous, you need only check the sign of
for values on the intervals (0, 3) and (3, 6).
We have, for instance
and
, which means the particle is moving the positive direction for
, or the interval (3, 6).
(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

which follows from the definition of absolute value. In particular, if
is negative, then
.
The total distance traveled is then 4 ft.
(g) Acceleration is the rate of change of velocity, so
is the derivative of
:

Compute the acceleration at
seconds:

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)
Answer:
I beleve the answer is 112/350 and x/100
I'm not sure how to find the percent (sorry) but I hope this helps :)
Answer:
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Step-by-step explanation:
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(2x+1)-1=0
Divide
2=0
Reitalizie
<em>2=0</em>
Reatomize
⊕∴∵
Reunatomize
2=0
It is not true
2=0