Answer:
Mass, m = 7.97 grams
Explanation:
We have,
Initial temperature was 34 degrees Celsius
Heat produced in it is 100 calories of heat
The specific heat capacity of water is 4.18 J/g °C
The heat produced due to change in temperature is given by :

m is mass of water in grams

So, 7.97 grams of water is required to produce heat of 2200 joules.
Answer:
V ≈ 646.50 L
General Formulas and Concepts:
<u>Chemistry - Gas Laws</u>
- Reading a Periodic Table
- Stoichiometry
- Combined Gas Law: PV = nRT
- R constant - 62.4 (L · torr)/(mol · K)
- Kelvin Conversion: K = °C + 273.15
Explanation:
<u>Step 1: Define</u>
RxN: N₂H₄ (g) + O₂ (g) → N₂ (g) + 2H₂O (l)
Given: 34.9 °C, 755.08 torr, 914.894 g H₂O
<u>Step 2: Identify Conversions</u>
Kelvin Conversion
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
Stoichiometry:
= 25.3955 mol N₂
Temperature: 34.9 + 273.15 = 308.05 K
<u>Step 4: Find Volume</u>
- Substitute variables: (755.08 torr)V = (25.3955 mol)(62.4 (L · torr)/(mol · K))(308.05 K)
- Multiply: (755.08 torr)V = 488160 L · torr
- Isolate <em>V</em>: V = 646.502 L
<u>Step 5: Check</u>
<em>We are given 5 sig figs as our lowest. Follow sig fig rules and round.</em>
646.502 L ≈ 646.50 L
Explanation:
Normally, fusion involves two heavy hydrogen nuclides but since we have 4 light hydrogen nuclides, two of which underwent positron emission, thus changing two protons into neutrons plus 2 positrons and 2 neutrinos. The resulting nucleus from this fusion reaction is an He-4 nucleus.
Answer for your question is;
2,6 = 8
The first shell is 2 electrons the other shell is 6 electrons