Answer:
1.2029 J/g.°C
Explanation:
Given data:
Specific heat capacity of titanium = 0.523 J/g.°C
Specific heat capacity of 2.3 gram of titanium = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
1 g of titanium have 0.523 J/g.°C specific heat capacity
2.3 × 0.523 J/g.°C
1.2029 J/g.°C
A hypothesis is a prediction of what you believe to be true.
Answer: It is non-spontaneous at all T.
Explanation:
According to Gibb's equation:
= Gibbs free energy = +ve
= enthalpy change = +ve
= entropy change = -ve
T = temperature in Kelvin
= +ve, reaction is non spontaneous
= -ve, reaction is spontaneous
= 0, reaction is in equilibrium
Putting in the values:
Reaction is non spontaneous at all temperatures.
<span>If I done the math correctly it is 3729J because you multiply 16.5 g by the 2260 J/g and get 3729 J</span>
1 hectoliter is 26.4172
1 kiloliter is 264.172
