This would be it i guess??
The first term of the sequence is already given to be 3. Use this value to obtain the second term.
a2 = 2(a1)^2 = 2(3)² = 18
Use the value of the second term to get the third term through the equation,
a3 = 2(a2)² = 2(18)² = 648
Thus, the answer to this item is letter B.
<span>The correct answer is option B. i.e. Both equation 1 and 2 have the same number of solutions. The equation 1 is |5x+6| = 41 By removing the modulus sign we get, 5x + 6 = 41 and 5x +6 = -41. Solving, 5x = 6 = 41 we get, 5x = 35 or x = 7. And, on solving 5x +6 = -41 we get, 5x = -47 or x = 9.4 Now. the second equation is |2x+13| = 28 By removing the modulus sign we get, 2x+ 13 = 28 and 2x +13 = -28. Solving, 2x = 28 -13 = 15 or x = 7.5 . And, on solving 2x +13 = -28 we get, 2x = -41 or x = -20.5.TH </span>
Y=3x+2 when x=-3
=> y= 3(-3)+2 = -9+2 =-7
