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3 years ago

Write the ratio in its simplest form. 1.4/7

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

8 0

1.4/7 in simplest form is 0.2/1 because you divide each side by 7.

Harlamova29_29 [7]3 years ago

3 0

1.4/7

Multiplying by 10

14/70 = 2/10 = 1/5

1/5 is the answer in its simplest form.

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Find the volume of a pyramid with a square base, where the side length of the base is 15.9\text{ cm}15.9 cm and the height of th

jeka94

Answer: 1,162.9 cm3

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Volume of a square pyramid: 1/3 x base area x height

Where

base area = base side length ^2

Replacing with the value given:

Base area = 15.9^2

base area : 252.81 cm2

Back with the volume formula:

V = 1/3 x base area x height

Replacing with the values given and solving for V (volume)

V = 1/3 x 252.81 x 13.8 = 1,162.9 cubic centimeters

Feel free to ask for more if needed or if you did not understand something.

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3 years ago

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cupoosta [38]

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Step-by-step explanation:

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2 years ago

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stiv31 [10]

2.5(12.75x + 24.50) = 188.75
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3 years ago

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NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the <u>zero-product property</u> and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the <u>second equation</u> and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

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10 months ago

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