Answer:
1. 
2. 
3. 
Step-by-step explanation:
Given information:


(1)
We need to find the value of P(s₁|I).





Therefore the value of P(s₁|I) is
.
(2)
We need to find the value of P(s₂|I).





Therefore the value of P(s₂|I) is
.
(3)
We need to find the value of P(s₃|I).





Therefore the value of P(s₃|I) is
.
To double the principle the formula is
2p=p e^rt
2=e^rt
2=e^0.12t
Solve for t
T=(log(2)÷log(e))÷0.12
T=5.78 years
In order from least to greatest:
5/10 , 7/12 , 4/6
You have to find a common denominator of all 3 numbers which is 60 and then you proceed with the next steps.
Answer: the number of shoppers on the first day is 125
Step-by-step explanation:
The number of shoppers is 20% more than the numbers of shoppers the day before. It means that the number of shoppers is increasing in geometric progression. The formula for determining the sum of n terms, Sn of a geometric sequence is expressed as
Sn = (ar^n - 1)/(r - 1)
Where
n represents the number of term in the sequence.
a represents the first term in the sequence.
r represents the common ratio.
From the information given,
r = 1 + 20/100 = 1.2
n = 4(first 4 days)
S4 = 671
Therefore, the expression for the first 4 days is
671 = (a × 1.2^(4) - 1)/1.2 - 1
671 = (a × 1.2^(4) - 1)/0.2
671 = 1.0736a/0.2
671 = 5.368a
a = 671/5.368
a = 125
Answer:
False
Step-by-step explanation: