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Allushta [10]
3 years ago
11

"Coal mines may contaminate groundwater in a location." What does this statement most likely represent?

Physics
2 answers:
Annette [7]3 years ago
8 0

Answer: an observation

Coal mining is a process of excavation of coal from the deeper layers of the earth crust. The mining process generally involves the unsaturated region but it adversely affect the saturated region, where groundwater reservoir is present. This results in the infiltration of the residues and sediments into the groundwater, hence contaminate it.

The given situation is an observation because it can be based upon facts and evidences.  


Aleks04 [339]3 years ago
5 0
By now ... 2018 ... after 200 years of experience and evidence,
it's an observation.
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Based on Nia's notes, what would be the BEST way to investigate the heat transfer based on the movement of the molecules?
allochka39001 [22]

Answer: Nia could measure the temperature of the bottom floor of a house to see if the heat had risen in the house due to convection.

Explanation:

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3 years ago
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Lin Yao looks at the back of a spoon. How should she describe her reflection?
Cerrena [4.2K]

The correct answer is C, right-side up and smaller.

It is the most common example of spherical mirrors. The inside of the spoon acts like a concave mirror and the back side of it like a convex mirror.

A convex mirror always forms a real and diminished image. That is, the image formed is erect or right-side up and smaller in size. Therefore, Lin Yao should describe her reflection on the back side of the mirror to be right-side up and smaller.

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4 years ago
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One block rests upon a horizontal surface. A second identical block rests upon the first one. The coefficient of static friction
goblinko [34]

Answer:

The magnitud of the force is 124.8N.

Explanation:

First we have to find the value of the static friction coefficient, when the external force F is applied to upper block (i will call it A Block) we have a free body diagram as the one shown in the figure i attached, so since this block has no aceleration in any direction the force F should be equal to the friction force between A and B block, one we noticed this we can use the equation for the Friction force to find the coefficient:

0=F-FrictionAB

F=FrictionAB=Nab*μs

and again, since the block has no acceleration the normal between A and B block should be equal to the weigth of the first block, so we have:

0=Nab-W

Nab=W=mg

replacing this we have:

F=μs*Nab=μs*mg=41.6N

and  μs=41.6N/(mg)

now it's time to see the free body diagram for the b block, if we now apply the F force to the B block the diagram should look like in the figure.

the color of the arrow gives you an idea of where the force comes from, the blue ones comes from the B block, the red ones from the A block and the brown ones from the ground.

now for the B block you can see two friction forces, one for the ground and one for the A block, both of these directed bacwards, and two normal forces, again one for the ground and one for the A block but the normal force for the A block is aiming downwards.

again we use the fact that the block is not accelerating in any direction so the sum of the forces in x and y direction have to be 0, so:

F-Friction1(ground)-Friction2(AB)=0

This is the new external F force that we are looking for:

F=Friction1(ground)+Friction2(AB)

we know Friction2(AB) because we found that in the previous block so:

F=Friction1(ground)+mg*μs

for the other friction we have to use the equation:

Friction(ground)=N(ground)*μs

from y axis we have:

N(ground)-w-Normal(AB)=0

N(ground)=w+Normal(AB)

we found the value of Normal(AB) with the previous block so:

N(ground)=mg+mg=2mg

and:

Friction(ground)=2mg*μs

F=Friction(ground)+mg*μs

F=2mg*μs+μs*mg=3mg*μs

and since: μs*mg=41.6N

the new F force would be:

F=3mg*μs=41.6*3=124.8N

4 0
3 years ago
A small metal object is tied to the end of a string and whirled round a circular path of radius 30cm. The object makes 20 oscill
LUCKY_DIMON [66]

Answer:

(i) The angular speed of the small metal object is 25.133 rad/s

(ii) The linear speed of the small metal object is 7.54 m/s.

Explanation:

Given;

radius of the circular path, r = 30 cm = 0.3 m

number of revolutions, n = 20

time of motion, t = 5 s

(i) The angular speed of the small metal object is calculated as;

\omega = \frac{20 \ rev}{5 \ s} \times \frac{2 \pi \ rad}{1 \ rev} = \frac{40\pi \ rad}{5 \ s} = 8\pi \ rad/s = 25.133 \ rad/s

(ii) The linear speed of the small metal object is calculated as;

v = \omega r\\\\v = 25.133 \ rad/s \ \times \ 0.3 \ m\\\\v = 7.54 \ m/s

6 0
3 years ago
Which statement describes a switch in an electrical circuit?
elena55 [62]

Answer:

It I’d B

Explanation:

Ape.x

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