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Veronika [31]
3 years ago
12

A block has a volume of 0.09 m3 and a density of 4,000 kg/m3. What's the force of gravity acting on the block in water?

Physics
2 answers:
12345 [234]3 years ago
5 0

                                       Density = (mass) / (volume)

                                4,000 kg/m³ = (mass) / (0.09 m³)

Multiply each side
by  0.09 m³ :           (4,000 kg/m³) x (0.09 m³) = mass

                                 mass = 360 kg .

Force of gravity = (mass) x (acceleration of gravity)

                           = (360 kg) x (9.8 m/s²)

                           = (360 x 9.8)  kg-m/s²

                           =   3,528 newtons . 

That's the force of gravity on this block, and it doesn't matter
what else is around it.  It could be in a box on the shelf or at
the bottom of a swimming pool . . . it's weight is 3,528 newtons
(about 793.7 pounds).

Now, it won't seem that heavy when it's in the water, because
there's another force acting on it in the upward direction, against
gravity.  That's the buoyant force due to the displaced water.

The block is displacing 0.09 m³ of water.  Water has 1,000 kg of
mass in a m³, so the block displaces 90 kg of water.  The weight
of that water is  (90) x (9.8) = 882 newtons (about 198.4 pounds),
and that force tries to hold the block up, against gravity.

So while it's in the water, the block seems to weigh

       (3,528  -  882) = 2,646 newtons  (about 595.2 pounds) .

But again ... it's not correct to call that the "force of gravity acting
on the block in water".  The force of gravity doesn't change, but
there's another force, working against gravity, in the water.
ratelena [41]3 years ago
5 0

Density = (mass) / (volume)


                               4,000 kg/m³ = (mass) / (0.09 m³)


Multiply each side

by  0.09 m³ :           (4,000 kg/m³) x (0.09 m³) = mass


                                mass = 360 kg .


Force of gravity = (mass) x (acceleration of gravity)


                          = (360 kg) x (9.8 m/s²)


                          = (360 x 9.8)  kg-m/s²


                          =   3,528 newtons .  


That's the force of gravity on this block, and it doesn't matter

what else is around it.  It could be in a box on the shelf or at

the bottom of a swimming pool . . . it's weight is 3,528 newtons

(about 793.7 pounds).


Now, it won't seem that heavy when it's in the water, because

there's another force acting on it in the upward direction, against

gravity.  That's the buoyant force due to the displaced water.


The block is displacing 0.09 m³ of water.  Water has 1,000 kg of

mass in a m³, so the block displaces 90 kg of water.  The weight

of that water is  (90) x (9.8) = 882 newtons (about 198.4 pounds),

and that force tries to hold the block up, against gravity.


So while it's in the water, the block seems to weigh


      (3,528  -  882) = 2,646 newtons  (about 595.2 pounds) .


But again ... it's not correct to call that the "force of gravity acting

on the block in water".  The force of gravity doesn't change, but

there's another force, working against gravity, in the water.



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Answer:

3.25 seconds

Explanation:

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h=-16t^2+vt+s

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When it hits the ground, h = 0

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It is a quadratic equation, we find the value of t,

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3 years ago
You throw a ball straight up. You are extra strong feeling today. It takes 11 seconds for the ball to come back down.
ollegr [7]

Answer:

A. 148.23 m

B. 2.75 m/s

Explanation:

The following data were obtained from the question:

Time of flight (T) = 11 s

Maximum height (h) =?

Initial velocity (u) =?

Next, we shall determine the time taken for the ball to get to the maximum height. This can be obtained as follow:

Time of flight (T) = 11 s

Time (t) to reach the maximum height =.?

T = 2t

11 = 2t

Divide both side by 2

t = 11/2

t = 5.5 s

NOTE: Time to reach the maximum height is the same as the time taken for the ball to fall back to the plane of projection.

A. Determination of the maximum height to which the ball was thrown.

Time (t) to reach maximum height = 5.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =?

h = ½gt²

h = ½ × 9.8 × 5.5²

h = 4.9 × 30.25

h = 148.23 m

B. Determination of the initial velocity.

Maximum height (h) reached = 148.23 m

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =?

u² = h/2g

u² = 148.23 / (2 × 9.8)

u² = 148.23 / 19.6

Take the square root of both side

u = √(148.23 / 19.6)

u = 2.75 m/s

5 0
2 years ago
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