Answer:
a) a = 7.72 m / s², N = 19.9 N and b) F = 25.5 N
Explanation:
To solve this problem we will use Newton's second law, let's set a reference system with an axis parallel to the plane and gold perpendicular axis. Let's break down the weight (W)
sin52 = Wx / W
cos52 = Wy / W
Wx = W sin52
Wy = w cos 52
Let's write them equations
X axis
Wx = ma
Y Axis
N-Wy = 0
N = Wy
a) Let's calculate the acceleration
a = W sin52 / m = mg sin 52 / m
a = g sin 52
a = 9.8 sin52
a = 7.72 m / s²
The force of the ramp is normal
N = Wy = mg cos 52
N = 3.3 9.8 cos 52
N = 19.9 N
b) For the block to move at constant speed the sum of force on the axis must be zero,
F - Wx = 0
F = Wx
F = mg sin52
F = 3.3 9.8 sin 52
F = 25.5 N
Parallel to the plane and going up
Answer:
Power, P = 722.96 watts
Explanation:
It is given that,
Voltage, V = 120 V
Length of nichrome wire, l = 8.9 m
Diameter of wire, d = 0.86 mm
Radius of wire, r = 0.43 mm = 0.00043 m
Resistivity of wire, 
We need to find the power drawn by this heater. Power is given by :

And, 


P = 722.96 watts
So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.
Answer:
117.6°
Explanation:
The vertical component of a force directed at some angle α from the vertical is ...
F·cos(α)
We want the vertical components of the wolf's force (Fw) and Red's force (Fr) to total zero. So for some angle from vertical α, Red's force will satisfy ...
Fw·cos(25°) + Fr·cos(α) = 0
cos(α) = -Fw/Fr·cos(25°) ≈ -(6.4 N)/(12.5 N)·0.906308 ≈ -0.464030
α ≈ arccos(-0.464030) ≈ 117.6°
Red was pulling at an angle of about 117.6° from the vertical.
_____
<em>Additional comment</em>
That's about 27.6° below the horizontal.
Radio waves are what cell phone company rely on
With the values you've given, only velocity can be found.
Acceleration is rate of change of velocity
d= 250s
t= 17s
a= d/t
=

= 4.7