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Alexandra [31]
3 years ago
7

How can accuracy be limited?

Physics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

accuracy refers to the deviation of a measurement from a standard or true value of the quantity being measured

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A 5.58 kg object with a speed of 35 m/s strikes a steel plate at an angle of 45.0 degrees with the normal to the plate, and rebo
MAVERICK [17]

Answer:

magnitude of vector is 276.19 kg m/s

Explanation:

The initial momentum is vector of magnitude

5.58 \times 35 = 195.3 (kg m/s)  And driven in a coherent manner with initial vector.

same magnitude is momentum after the impact, but it is oriented perpendicularly to initial momentum vector.

So, you have 2 momentum vector of  specified magnitude perpendicular to one another.

 The contrast between such two vectors is a right angle triangle hypotenuse of 195.3 sides

magnitude of vector is  \sqrt{ 195.3^2 + 195.3^2} = 276.19

8 0
3 years ago
Hair color is a trait that’s controlled by many genes working together. Each gene contributes to this trait only in a small prop
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The correct answer should be polygenic inheritance

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4 years ago
Read 2 more answers
A bar-magnet with magnetic moment 2.5 Am^2 is placed in a homogeneous magnetic field (of 0.1 T that is directed along the z-axis
Angelina_Jolie [31]

Answer:

1)

Force on bar magnet  = 0

Torque on bar magnet = 0

2)

Force on bar magnet  = 0

Torque on bar magnet = 0.177 Nm

3)

Force on bar magnet  = 0

Torque on bar magnet = 0.25 Nm

Explanation:

Part 1)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is inclined along z axis along magnetic field

then we will have

\tau = MBsin0 = 0

Part 2)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is pointing 45 degree with z axis then we will have

\tau = MBsin45

\tau = (2.5)(0.1)sin45

\tau = 0.177 Nm

Part 3)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is pointing 90 degree with z axis then we will have

\tau = MBsin90

\tau = (2.5)(0.1)sin90

\tau = 0.25 Nm

8 0
4 years ago
Physical Science AIS - AE 20-21-Kotal / Unit 2: Reactions and Radioactivity / The Environment
astraxan [27]

Answer:19

Explanation:

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3 years ago
You lift your pet cat vertically by 2m and then you lower it vertically by 2m .during this exercise is the total work done by gr
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Zero, cause the positive and negative work cancel out :)
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