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vichka [17]
3 years ago
11

A sailboat is underway in the fog. what sound signal should you hear?

Physics
2 answers:
Rufina [12.5K]3 years ago
8 0
The conventional signal used by sailboats in conditions of reduced visibility such as heavy fog is one long blast followed by two short blasts.

The blasts help other boat operators locate one another's vessel in a condition where it is not easy to see. This signal is repeated in order to not only let others know of the vessel's position, but also help them know which way it is traveling. For example, if the blasts start to become distant, then the sailboat is travelling away from you.
Wittaler [7]3 years ago
4 0

The ordinary sign utilized by sailboats in states of reduced visibility for example heavy fog is one large Blasts followed by two short blast.

Further Explanation:

Horns in Foggy Conditions:

In foggy conditions you hear one delayed blast in addition to two short impacts at regular intervals of 2 minutes.

Personal Safety During Fog:  

 Have all the team put on life jackets, as there will brief period if a collision happens

 Consider carefully before having the team cut on [safety harnesses], as they should probably to jump clear in a collision.

 On the off chance that the climate is unpleasant, the greater danger of falling overboard may require harnesses to be used.

 The life-raft should be at the ready for moment discharge if necessary.

 Have red and white flares nearby.  

 In quiet climate, think about putting the dinghy over the side, [ towing it astern ] and being accessible in the case of a collision  

Fog Forecasting:

An exact method for fog forecasting is the utilization of a hygrometer to discover the dew point temperature of the air.

Answer Details:

Subject: Physics

Level: High School

Key Words:

Horns in Foggy Conditions:

Personal Safety During Fog:  

Fog Forecasting

For further Evaluation:

brainly.com/question/5144573

brainly.com/question/112785

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A boy im50kg at rest on a skateboard is pushed by another boy who exerts a force of 200 N on him. If the first boy's
sergey [27]

Answer:

Time, t = 2 seconds

Explanation:

Given the following data;

Mass, m = 50 kg

Initial velocity, u = 0 m/s (since it's starting from rest).

Final velocity, v = 8 m/s

Force, F = 200 N

To find the time, we would use the following formula;

F = \frac {m(v - u)}{t}

Making time, t the subject of formula, we have;

t = \frac {m(v - u)}{F}

Substituting into the formula, we have;

t = \frac {50(8 - 0)}{200}

t = \frac {50*(8)}{200}

t = \frac {400}{200}

Time, t = 2 seconds

5 0
3 years ago
Calculate the energy absorbed when 13 kg of liquid water raises from 18°C to 100°C and then boils at 100°C.
Cloud [144]

Answer:

the energy absorbed is 4.477 x 10⁶ J

Explanation:

mass of the liquid, m = 13 kg

initial temperature of the liquid, t₁ = 18 ⁰C

final temperature of the liquid, t₂ = 100 ⁰C

specific heat capacity of water, c = 4,200 J/kg⁰C

The energy absorbed is calculated as;

H = mcΔt

H = mc(t₂ - t₁)

H = 13 x 4,200(100 - 18)

H = 4.477 x 10⁶ J

Therefore, the energy absorbed is 4.477 x 10⁶ J

5 0
3 years ago
A solar cell, 3.0 cm square, has an output of 350 mA at 0.80 V when exposed to full sunlight. A solar panel that delivers close
Vesna [10]

Answer:

You will need 450 cells (3 cm each) to meet the voltage/current requirement.

The panel must be 3 cells in one side, by 150 cell in another side. 1350 cm^2 or 0.135 m^2. They must be connected 3 in row in parallel (to add current), then each of the former group must be connected in series to meet the voltage, so it would be 150 rows of connected in series.

The panel can be optimized using a voltage inverter, to convert current to voltage. In this way, less cells can be used achieving the same output specs.

Explanation:

To meet the voltage:

120 [v] required voltage

0.8 [v] voltage of each cell

\frac{120}{0.8} =150[v]\\

So we need 150 cells in series for the voltage.

To meet the current

1.0 [A]      Required current

350[mA]=0.35[A] cell current

1/0.35=3 cell So we need 3 cells in parallel to add the currents and meet the requirement.

See the attached figure

8 0
3 years ago
The number of wave troughs that pass by every second is a wave's _________.
professor190 [17]
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scoray [572]

Answer:

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