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vichka [17]
3 years ago
11

A sailboat is underway in the fog. what sound signal should you hear?

Physics
2 answers:
Rufina [12.5K]3 years ago
8 0
The conventional signal used by sailboats in conditions of reduced visibility such as heavy fog is one long blast followed by two short blasts.

The blasts help other boat operators locate one another's vessel in a condition where it is not easy to see. This signal is repeated in order to not only let others know of the vessel's position, but also help them know which way it is traveling. For example, if the blasts start to become distant, then the sailboat is travelling away from you.
Wittaler [7]3 years ago
4 0

The ordinary sign utilized by sailboats in states of reduced visibility for example heavy fog is one large Blasts followed by two short blast.

Further Explanation:

Horns in Foggy Conditions:

In foggy conditions you hear one delayed blast in addition to two short impacts at regular intervals of 2 minutes.

Personal Safety During Fog:  

 Have all the team put on life jackets, as there will brief period if a collision happens

 Consider carefully before having the team cut on [safety harnesses], as they should probably to jump clear in a collision.

 On the off chance that the climate is unpleasant, the greater danger of falling overboard may require harnesses to be used.

 The life-raft should be at the ready for moment discharge if necessary.

 Have red and white flares nearby.  

 In quiet climate, think about putting the dinghy over the side, [ towing it astern ] and being accessible in the case of a collision  

Fog Forecasting:

An exact method for fog forecasting is the utilization of a hygrometer to discover the dew point temperature of the air.

Answer Details:

Subject: Physics

Level: High School

Key Words:

Horns in Foggy Conditions:

Personal Safety During Fog:  

Fog Forecasting

For further Evaluation:

brainly.com/question/5144573

brainly.com/question/112785

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7 0
3 years ago
Consider a simple pendulum with a period
lisabon 2012 [21]

Answer:

1. The length is 8.35m

2. The period on the moon is 14.05 secs

Explanation:

1. Data obtained from the question. This includes the following:

Period (T) = 5.8 secs

Acceleration due to gravity (g) = 9.8 m/s2

Length (L) =...?

The length can be obtained by using the formula given below:

T = 2π√(L/g)

5.8 = 2π√(L/9.8)

Take the square of both side

(5.8)^2 = 4π^2 x L/ 9.8

Cross multiply

4π^2 x L = (5.8)^2 x 9.8

Divide both side by 4π^2

L = (5.8)^2 x 9.8 / 4π^2

L= 8.35 m

2. Data obtained from the question. This includes the following:

Acceleration due to gravity (g) = 1.67 m/s2

Length (L) = 8.35m (the length remains the same)

Period (T) =?

The period can be obtained as follow:

T = 2π√(L/g)

T = 2π√(8.35/1.67)

T = 14.05 secs

Therefore, the period on the moon is 14.05 secs

4 0
3 years ago
The magnitude of the magnetic flux through the surface of a circular plate is 5.90 10-5 T · m2 when it is placed in a region of
valkas [14]

Answer:

The strength of the magnetic field is 3.5 x 10⁻³ T

Explanation:

Given;

magnitude of the magnetic flux , Φ = 5.90 x 10⁻⁵ T·m²

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radius of the circular plate, r = 8.50 cm = 0.085 m

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Φ = BACosθ

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A = π (0.085)² = 0.0227 m²

The strength of the magnetic field:

B = Φ / ACosθ

B = ( 5.90 x 10⁻⁵) / ( 0.0227 x Cos42)

B = 3.5 x 10⁻³ T

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