A 10 Kg ball is rolling at 2.5 m/s. It is then hit from behind with a bat that puts a 300 N force on the ball for a quick .3 sec
1 answer:
You might be interested in
Answer:
The height is : 60.025 m
Explanation:
The flowerpot falls off the balcony with zero launch angle
Given the time of fright as 3.5 s then ;
The formula to apply is ;
3.5²= 2H/9.8
12.25 =2H/9.8
12.25 * 9.8 = 2H
120.05 = 2H
120.05/2 = H
60.025 =H
Answer:
The observer sees the space-probe 9.055m long.
Explanation:
Let be the length of the space-probe when measured at rest, and
be its length as observed by an observer moving at velocity
, then
Now, we know that and
, and putting these into
we get:
Thus, an observer moving at 0.95c observes the space-probe to be 9.055m long.