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Tamiku [17]
3 years ago
12

A cable with mass 0.5 kilograms per meter (kg/m) is used to lift 150 kg of coal up a mine shaft 50 meters deep. Set up the integ

ral that will calculate the work needed to lift the load one quarter of the way up the shaft. (Set up the integral only, no need to compute its value.)
Physics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

W=-\int_{0}^{50}[150-0.5y]dy

Explanation:

the integral for the work is:

W=\int\vec{F}\cdot d\vec{l}=\int(-M(y)g)dy

the work is against the gravitational force. While the coal is going up, M(y) is changing due to the length of the cable is lower. We can describe this by using the following formula

M(y)=150kg-0.5\frac{kg}{m}y

Thus , the integral for the work is:

W=-\int_{0}^{50}[150-0.5y]dy

hope this helps!!

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The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's moti
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Answer:

B

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You are at the edge of a diving board that is 9 meters above the water. If you weigh 500 Newtons, what is your potential energy?
Semenov [28]

Answer:

4500 J

Explanation:

First, let's define some equations and derivations.

Our potential energy formula is:

  • \displaystyle U = mgh

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We also know that <em>mg</em> is equal to the weight of an object (in N), from Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration).

Therefore, we can simply substitute force into the equation:

  • \displaystyle U = Fh

Where <em>F</em> is the force (in N) and <em>h</em> is still height (in m).

Now we can calculate the amount of potential energy in our system, measured in joules.

Substitute in the given variables, F = 500 N and h = 9 m:

  • \displaystyle U = (500 \ N)(9 \ m)

Using simple Pre-Algebra rules, we find that:

  • \displaystyle U = 4500 \ J

This tells us that the we have 4500 joules of potential energy when I am 9 meters above the water on the edge of the diving board.

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3 years ago
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A petrol tanker ha 2800kg when empty and hold 30m3 0f petrol when full. The denity of petrol i 740kg/m3. Calculate the ma of the
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The mass of the tanker with petrol is 250000 N.

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Volume of petrol= v =30 m³

Density of petrol= d =740 kg/m³

Thus , mass , density and volume relation can be given as,

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Mass = Density × Volume

Mass = 740× 30

Mass = 22200 kg

The mass of the petrol is 22200 kg.

Total mass of tanker with petrol = Mass of petrol + Mass of tanker

Total mass of tanker with petrol= 22200+ 2800 kg

Total mass of tanker with petrol= 25000 kg

Total weight of the tanker with petrol = Mass of tanker full of petrol× g

Where, weight = m × g ,(g =10m/s²)

Total weight of the tanker with petrol= 25000×10 = 250000 N

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4 0
1 year ago
Find the radius Rrigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×
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Answer:

r = 1.61 x 10^{11} m

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energy radiated (H) = 2.7 x 10^31 W

surface temperature (T)  = 11,000 k

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we can find the radius of the star from the equation below

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therefore  the equation becomes

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r = \sqrt{\frac{2.7 x 10^31}{4 x π x 1 x 5.67 x 10^{-8}  x (11,000)^{4}} }

r = 1.61 x 10^{11} m

       

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