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gladu [14]
3 years ago
5

Help me please. I don't understand this at all

Physics
2 answers:
algol133 years ago
7 0
The answer is C for this question
SCORPION-xisa [38]3 years ago
7 0
I think the answer would be c; <span>compaction and cementation</span>
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What is the control group
kolbaska11 [484]

Answer: the group in an experiment that doesn’t get treatment

Explanation:

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2 years ago
A wave will "break" because ________. a wave will "break" because ________. the sediment load of water is greater near the shore
vodka [1.7K]
A wave will "break" because the bottom interferes with its oscillatory motion. Breaking of waves may occur anywhere that the amplitude is sufficient, including in mid-ocean. When waves enter shallow water they break because the motion of water in lower part of the wave nearest the bottom is slowed by friction so that their oscillation is faster than its supporting portion at the bottom. Thus, the wave collapses forward and breaks.

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3 years ago
Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ
Sergio039 [100]

Answer:

\lambda_{B}=414.67 nm

Explanation:

In this question we have given

\lambda_{A}=622nm

we have to find

\lambda_{B}=?

We know that

optical path difference for bright fringe is given as=n\lambda

Here,

n is order of fringe

and optical path difference for dark fringe is given as=(n+.5)\lambda

since the light with wavelength \lambda_{A} produces its third-order bright fringe at the same place where the light with wavelength \lambda_{B} produces its fourth dark fringe  

it means

optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe

Therefore,

3\lambda_{A}=(4+.5)\lambda_{B}...............(1)

Put value of \lambda_{A} in equation (1)

3 \times 622=(4+.5)\lambda_{B}

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\lambda_{B}=414.67 nm

3 0
3 years ago
Can someone help me with accerleration
dangina [55]

Answer:

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SI unit: m/s2, m·s−2, m s−2

6 0
3 years ago
Read 2 more answers
How are frequency, wavelength, and energy related? Choose all that apply.
marta [7]

Explanation:

The energy of a wave is given by :

E=\dfrac{hc}{\lambda}

Where

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Energy is inversely proportional to wavelength. Also, the relation between frequency and wavelength is inverse.

If the frequency is high, the wavelength will be shorter.

Hence, the correct options are :

Higher frequencies have shorter wavelengths.

Shorter wavelengths have lower energy.

Lower frequencies have lower energy.

7 0
3 years ago
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