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svp [43]
3 years ago
14

How are magic minerals different from Felsic minerals?

Chemistry
2 answers:
malfutka [58]3 years ago
7 0

Answer:

c

Explanation:

Anuta_ua [19.1K]3 years ago
3 0

Answer:

Mafic minerals contain more dark-colored, high-density minerals.

Explanation:

Mefic and felsic minerals represent two kinds of minerals or lava.

For example, mefic lava is more viscous than felsic lava.

The other difference is that word mafic is related to presence of Magnesium and iron minerals more while in felsic (Feldspar) silica content is more.

Mefic minerals are associated with dark color while felsic are lighter in color.

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A(n) 816 ml sample of hydrogen was collected over water at 21.0◦c on a day when the barometric pressure was 755 torr. what volum
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The correct answer is A

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If you start with 163 g of water at 29◦C, how much heat must you add to convert all the liquid into vapor at 100◦C? Assume no he
Snowcat [4.5K]

Answer:

48.37514 kj

Explanation:

Given data:

Mass of water = 163 g

Initial temperature = 29°C

Final temperature = 100°C

Heat added = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

ΔT =  100°C - 29°C

ΔT =  71°C

Q = 163 g × 4.18 j/g.°C × 71°C

Q = 48375.14 j

Joule to Kj conversion:

48375.14 /1000 = 48.37514 kj

3 0
3 years ago
Liquid nitrogen becomes a gas when it is poured out of its container. The nitrogen is
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Answer:

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Explanation:

7 0
3 years ago
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By what method do we measure the distance to objects that are a few thousand light-years away?
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Answer:

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A resting adult requires about 240 ml of pure oxygen/mind and breathes about 12 times every minute. if inhaled air contains 20 p
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12 times breathe give 240 ml of pure O_{2}. Each breathe gives 20 ml of O_{2}.

Let us consider, volume of air per breathe= x ml.

Pure O_{2} from inhaled air= \frac{20}{100}x ml and Pure O_{2} from exhaled air= \frac{16}{100}x ml.

Pure O_{2} from inhaled and exhaled air= 20 ml

So, \frac{20}{100}x + \frac{16}{100}x = 20

Therefore, x = 55.5 ml

So, volume of air per breath= 55.5 ml.


7 0
3 years ago
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