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3 years ago

How are magic minerals different from Felsic minerals?

Chemistry

2 answers:

malfutka [58]3 years ago

7 0

Answer:

Explanation:

Anuta_ua [19.1K]3 years ago

3 0

Answer:

Mafic minerals contain more dark-colored, high-density minerals.

Explanation:

Mefic and felsic minerals represent two kinds of minerals or lava.

For example, mefic lava is more viscous than felsic lava.

The other difference is that word mafic is related to presence of Magnesium and iron minerals more while in felsic (Feldspar) silica content is more.

Mefic minerals are associated with dark color while felsic are lighter in color.

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Consider the second-order reaction:

kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

Explanation:

$2HI(g)\rightarrow H_2(g)+I_2(g)
$

Rate Law: $k[HI]^2
$

Rate constant of the reaction = k = $6.4\times 10^{-9} L/mol s$

Order of the reaction = 2

Initial rate of reaction = $R=1.6\times 10^{-7} Mol/L s$

Initial concentration of HI = $[A_o]$

$1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2$

$[A_o]=5 mol/L$

Final concentration of HI after t = [A]

t = $4.53\times 10^{10} s$

Integrated rate law for second order kinetics is given by:

$\frac{1}{[A]}=kt+\frac{1}{[A_o]}$

$\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}$

$[A]=0.00345 mol/L$

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

5 0

3 years ago

I NEED HELP PLEASE, THANKS! :)

marin [14]

Answer:

$\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}$

Explanation:

1. Calculate the moles of copper(II) hydroxide

$\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}$

2. Calculate the molecules of copper(II) hydroxide

$\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}$

6 0

3 years ago

A person's heart beats 72 times a minute. At this rate, how many times does it beat in one hour?

sesenic [268]

At one minute, a persons's heart beats 72 times.

Therefore, in one hour or 60 minutes, a person's heart will beat (60×72) times, i.e., 4320 times

Answer is 4320 times

6 0

2 years ago

Which of the following terms refers to the number of moles of solute per liter of solution?

Anika [276]

Molarity
Molarity is a unit used to express the concentration of a substance, and it is defined as the number of moles of solute per decimeter cubed (liter) of solvent.

5 0

3 years ago

The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

ololo11 [35]

The allowable combination for the atomic orbital is n=3, l=1 or 2, $m_{l}$ =+1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; $m_{l}$ values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Hence, the l value must be lower than 3. Because of $m_{l}$ = +1, the l value must be higher than 0. Two l values are consistent with n and $m_{l)$ values:

l= 1 or 2

Therefore, the allowable condition is n=7, l=1 or 2, $m_{l}$ =+3.

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

7 0

1 year ago