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erastova [34]
3 years ago
15

If an athlete weighs 147 lb and has 15.0 % body fat by weight, how many pounds of fat does the athlete's body contain?

Chemistry
1 answer:
V125BC [204]3 years ago
7 0
I think I answered a question just like this the other day. To get the weight of the body fat, multiply the total body weight by the percentage of the body fat (as a decimal, which would be 0.15).
So, you would do this:
147x0.15=22.05
The athlete's body contains 22.05 pounds of fat.
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balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, w
kotegsom [21]

Answer:

The answer to your question is V2 = 3.7 L

Explanation:

Data

Volume 1 = 3.5 L

Temperature 1 = 25°C

Temperature 2 = 40°C

Pressure = cte.

Volume 2 = ?

Formula

To solve this problem use the Charles' law

             V1/T1 = V2/T2

- Solve for V2

             V2 = V1T2 / T1

- Convert temperature to °K

Temperature 1 = 25 + 273 = 298°K

Temperature 2 = 40 + 273 = 313°K

- Substitution

              V2 = (3.5)(313) / 298

- Simplification

              V2 = 1095.5 / 298

- Result

              V2 = 3.7 L

8 0
3 years ago
Read 2 more answers
How many electrons can be held in sub level I=3?
Zinaida [17]
2 is your answer hope you get it right
6 0
3 years ago
When 3.4 moles of hydrogen gas react with excess oxygen how many moles of water will be produced
s344n2d4d5 [400]
1. start with balanced equation.
2 H2(g) + O2(g<span>) </span><span> 2 H</span>2O(g<span>)
</span>
2. Use stoichiometry 
(3.4moles of H)(2moles of H2O/2moles of H)
The moles of H will cancel, leaving you with moles of H2O. 
The answer is 3.4 moles of H2O
6 0
4 years ago
The energy of any one-electron species in its nth state (n = principal quantum number) is given by E = –BZ2 /n2 where Z is the c
Ivahew [28]

Explanation:

(a) The given data is as follows.

            B = 2.180 \times 10^{-18} J

            Z = 4 for Be

Now, for the first excited state n_{f} = 2; and n_{i} = \infinity if it is ionized.

Therefore, ionization energy will be calculated as follows.

         I.E = \frac{-Bz^{2}}{\infinity^{2}} - (\frac{-2.180 \times 10^{-18} J /times (4)^{2}}{(2)^{2}})

              = 8.72 \times 10^{-18} J

Converting this energy into kJ/mol as follows.

           8.72 \times 10^{-18} J \times 6.02 \times 10^{23} mol  

           = 5249 kJ/mol

Therefore, the ionization energy of the Be^{3+} ion in its first excited state in kilojoules per mole is 5249 kJ/mol.

(b) Change in ionization energy is as follows.

         \Delta E = -Bz^{2}(\frac{1}{(4)^{2}} - {1}{(2)^{2}}) = \frac{hc}{\lambda}

   \frac{hc}{\lambda} = 0.1875 \times 2.180 \times 10^{-18} J \times (4)^{2}                

        \lambda = \frac{6.626 \times 10^{-34} \times 2.998 \times 10^{8} m/s}{0.1875 \times 2.180 \times 10^{-18} J \times 16}

                     = 303.7 \times 10^{-10} m

or,                 = 303.7^{o}A

Therefore, wavelength of light given off from the Be^{3+} ion by electrons dropping from the fourth (n = 4) to the second (n = 2) energy levels 303.7^{o}A.

5 0
3 years ago
According to the National Institute of Health, ventricular tachycardia is a fast, regular beating of the ventricles that may las
jarptica [38.1K]

Answer:

1 makes the most sense

Explanation:

There is no way blood pressure will be decreased especially if your ventricles are erratically contracting for a long period of time. So 3 and 4 are out. And you said number 2 is wrong so my finally answer is 1.

3 0
3 years ago
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