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erastova [34]
3 years ago
15

If an athlete weighs 147 lb and has 15.0 % body fat by weight, how many pounds of fat does the athlete's body contain?

Chemistry
1 answer:
V125BC [204]3 years ago
7 0
I think I answered a question just like this the other day. To get the weight of the body fat, multiply the total body weight by the percentage of the body fat (as a decimal, which would be 0.15).
So, you would do this:
147x0.15=22.05
The athlete's body contains 22.05 pounds of fat.
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Masteriza [31]

Answer:

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7 0
3 years ago
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Which type of reaction occurs in the following equation?
Tema [17]
The  type  of  reaction  which  occurs  is  referred to  as  redox  reaction.  This  kind  of  reaction  involve  both  oxidation  and  reduction.
Al(s)  is  oxidized  to  alluminium  ions,  while  cu2+  is reduced  copper metal.Reduction  occurs   at  the  cathode  while oxidation  occurs at  the anode.

3 0
3 years ago
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How many moles of FeCI3 are present in 345.0 g FeCI3
Sphinxa [80]

Answer:

\boxed {\boxed {\sf About \ 2.127 \ moles \ of \ FeCl_3}}

Explanation:

To convert from moles to grams, the molar mass must be used.

1. Find Molar Mass

The compound is iron (III) chloride: FeCl₃

First, find the molar masses of the individual elements in the compound: iron (Fe) and chlorine (Cl).

  • Fe:  55.84 g/mol
  • Cl:  35.45 g/mol

There are 3 atoms of chlorine, denoted by the subscript after Cl. Multiply the molar mass of chlorine by 3 and add iron's molar mass.

  • FeCl₃: 3(35.45 g/mol)+(55.84 g/mol)=162.19 g/mol

This number tells us the grams of FeCl₃ in 1 mole.

2. Calculate Moles

Use the number as a ratio.

\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}

Multiply by the given number of grams, 345.0.

345.0 \ g \ FeCl_3 *\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}

Flip the fraction so the grams of FeCl₃ will cancel.

345.0 \ g \ FeCl_3 *\frac{1 \ mol \ FeCl_3}{162.19 \ g \ FeCl_3}

345.0 *\frac{1 \ mol \ FeCl_3}{162.19 }

\frac{345.0 \ mol \ FeCl_3}{162.19 }

Divide.

2.12713484 \ mol \ FeCl_3

3. Round

The original measurement of grams, 345.0, has 4 significant figures. We must round our answer to 4 sig figs.

For the answer we calculated, that is the thousandth place.

The 1 in the ten thousandth place tells us to leave the 7 in the thousandth place.

\approx 2.127 \ mol \ FeCl_3

There are about <u>2.127 mole</u>s of iron (III) chloride in 345.0 grams.

6 0
3 years ago
a. For the reaction 2H2 + 02→ 2H20, how many moles of water can be produced from 6.0 mol of oxygen? 2.0 mol b. 6.0 mol 12 mol d.
pickupchik [31]

Explanation:

from the equation 1 mole of O2 will give 2 moles of H2O then 6.0 moles of O2 will give x

6.0*2 moles/ 1 mole

= 12 moles

this implies that, 6.0 moles of O2 will give = 12 moles of water

3 0
3 years ago
Calculate the volume of 2.65 moles of N2O gas at STP.
Reptile [31]

Answer:

63.6 dm³

Explanation:

Volume of gas= no. of moles ×24dm³

Thus, volume of N₂O

= 2.65 × 24

= 63.6 dm³

3 0
3 years ago
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