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Alexeev081 [22]
2 years ago
14

By what method do we measure the distance to objects that are a few thousand light-years away?

Chemistry
2 answers:
Zigmanuir [339]2 years ago
8 0

Answer:

i believe the answer to your question is parallax or parsecs. im sorry im not very specific in this!

Explanation:

Wewaii [24]2 years ago
8 0
First, a dirty little secret: scientists don't actually measure astronomical distances in light years. Rather, they measure them in a unit called the Parsecs
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Form a bond: Each electron has a charge of 1–, and each proton has a charge of 1+. You can calculate the charge of an atom by su
Shtirlitz [24]

Explanation:

Bond forming:

   Given species:

             Na - Sodium              Cl - Chlorine

 Na has a valence electron  

 Cl has 7 valence electron

To form a bond of this nature, there must be a transfer of electrons.

 Here, the bond is between a metal and non-metal

The metal is sodium and the non-metal is chlorine;

  Na         →     Na⁺  +   e⁻                                           loss of 1 electron

2,8,1               2,8

                  isoelectronic with Neon

Cl  + e  →   Cl⁻                                                              gain of one electron

               isoelectronic with Argon

  Na⁺  +  Cl⁻   →   Na⁺.Cl⁻

  This bond type is an ionic bond

5 0
2 years ago
Read 2 more answers
A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in
LenKa [72]

Answer:

P=3.7atm

Explanation:

Hello,

In this case, it is possible to determine the pressures of both helium and neon as shown below:

n_{He}=\frac{P_{He}V_{He}}{RT}=\frac{5.6atm*3.0L}{0.082\frac{atm*L}{mol*K}*298.15K} =0.688molHe\\\\n_{Ne}=\frac{P_{Ne}V_{Ne}}{RT}=\frac{3.6atm*4.5L}{0.082\frac{atm*L}{mol*K}*298.15K}=0.663molNe

Now, one considers the total moles (addition between both neon's and helium's moles) and the total volume to compute the final pressure as shown below:

P=\frac{n_TRT}{V_T} =\frac{(0.688+0.663)mol*0.082\frac{atm*L}{mol*K}*298.15K}{9.0L}=3.7atm

Best regards.

8 0
2 years ago
Carbon dioxide in the oceans is affecting its pH.<br><br> a. True<br> b. False
monitta
Its true it affects the pH balance
7 0
2 years ago
The half-life of phosphorus-32 is 14.30 days. how many milligrams of a 20.00 mg sample of phosphorus-32 will remain after 85.80
ZanzabumX [31]
The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.

             A(t) = A(o) (1/2)^(t/d)

where t is the certain period of time. Substituting the known values,

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Solving,

           A(t) = 0.3125 mg

Hence, the answer is 0.3125 mg. 
7 0
3 years ago
Which of the following describes scientists?
serious [3.7K]
I believe the answer I’d D

Hope it helps
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3 years ago
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