-10.3 since you multiply 1.67 by ten first by doing that it moves the decimal to the right so its 16.7 then subtract 27 which would give you the answer of -10.3
Answer:
[Fe(NO₃)₃] = 0.90 M
Explanation:
Molarity = Mol/L
Total volume of solution: 31.65 mL + 44.96 mL = 76.61 mL
Let's determine the moles of salt ([M] . volume)
0.03165 L . 1.07M = 0.0338 moles
0.04496L . 0.79M = 0.0355 moles
Total moles Fe(NO₃)₃ = 0.0338 + 0.0355 = 0.0693 moles
Volume of solution = 76.61 mL = 0.07661 L
0.0693 mol / 0.07661 L = 0.90 mol/L
In a series of columns, or groups, and rows, or periods.
Answer:
779 g of chlorine would produce 7.3 moles of AlCl₃
Explanation:
Given data:
Mass of chlorine gas = 779 g
Number of moles of Aluminium chloride formed = ?
Solution:
Chemical equation:
2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂
<em>Number of moles of chlorine:</em>
Number of moles = mass/ molar mass
Number of moles = 779 g/ 71 g/mol
Number of moles = 11 mol
Now we will compare the moles of chlorine with Aluminium chloride.
Cl₂ : AlCl₃
3 : 2
11 : 2/3×11 = 7.3 mol
779 g of chlorine would produce 7.3 moles of AlCl₃.